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MrRa [10]
2 years ago
14

an electron, a proton and a deuteron move in a magnetic field with same momentum perpendicularly. the ratio of the radii of thei

r circular paths will be -
Physics
1 answer:
wel2 years ago
6 0

If an electron, a proton, and a deuteron move in a magnetic field with the same momentum perpendicularly, the ratio of the radii of their circular paths will be:

  • 1: √2 : 1

<h3>How is the ratio of the perpendicular parts obtained?</h3>

To obtain the ratio of the perpendicular parts, one begins bdy noting that the mass of the proton = 1m, the mass of deuteron = 2m, and the mass of the alpha particle  = 4m.

The ratio of the radii of the parts can be obtained by finding the root of the masses and dividing this by the charge. When the coefficients are substituted into the formula, we will have:

r = √m/e : √2m/e : √4m/2e

When resolved, the resulting ratios will be:

1: √2 : 1

Learn more about the radii of their circular paths here:

brainly.com/question/16816166

#SPJ4

​

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You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30 degre
katen-ka-za [31]
To calculate the velocity of the sound wave, we use this formula:
V = 331 + [0.6*T], 
Where V is the velocity and T represents temperature.
When the temperature is 36 degree Celsius, we have 
V = 331 + [0.6 * 36]
V = 331 + 21.6 = 352.6 
Therefore, V = 352.6 m/s.
7 0
3 years ago
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El espectro visible en el aire está comprendido entre la longitud de onda 450 nm del color azul, Determina la velocidad de propa
TiliK225 [7]

Answer:

v = 2,99913 10⁸ m / s

Explanation:

The velocity of propagation of a wave is

         v = λ f

in the case of an electromagnetic wave in a vacuum the speed that speed of light

         v = c

When the wave reaches a material medium, it is transmitted through a resonant type process, whereby the molecules of the medium vibrate at the same frequency as the wave, as the speed of the wave decreases the only way that they remain the relationship is that the donut length changes in the material medium

         λ = λ₀ / n

where n is the index of refraction of the material medium.

Therefore the expression is

           v = \frac{\lambda_o}{n} f

Let's look for the frequency of blue light in a vacuum

           f =\frac{c }{\lambda_o}  

           f = \frac{3 \ 10^8}{450 \ 10^{-9}}

           f = 6.667 10¹⁴ Hz

the refractive index of air is tabulated

           n = 1,00029

let's calculate

           v = \frac{450 \ 10^{-9} }{1.00029}  \ 6.667 \ 10^{14}450 10-9 / 1,00029 6,667 1014

            v = 2,99913 10⁸ m / s

we can see that the decrease in speed is very small

8 0
2 years ago
In the 25 ft Space Simulator facility at NASA's Jet Propulsion Laboratory, a bank of overhead arc lamps can produce light of int
Aleonysh [2.5K]

Answer:

a) <em>8.33 x 10^-6 Pa</em>

b) <em>8.23 x 10^-11 atm</em>

c) <em>1.67 x 10^-5 Pa</em>

d) <em>1.65 x 10^-10 atm</em>

<em></em>

Explanation:

Intensity of the light I = 2500 W/m^2

speed of light c<u> </u>= 3 x 10^8 m/s

a) we know that the pressure for for a totally absorbing surface is given as

P_{abs} = I/c = 2500/(3 x 10^8) = <em>8.33 x 10^-6 Pa</em>

b) 1 atm = 101325 Pa

P_{abs} = (8.33 x 10^-6)/101325 = <em>8.23 x 10^-11 atm</em>

c) for a totally reflecting surface

P_{ref} = 2I/c = twice the value for totally absorbing

P_{ref}  = 2 x 8.33 x 10^-6 = <em>1.67 x 10^-5 Pa</em>

d)  1 atm = 101325 Pa

P_{ref} = 2 x 8.23 x 10^-11  = <em>1.65 x 10^-10 atm</em>

8 0
3 years ago
The hairdryer has a plastic case so there is no need for an earth wire connection in the plug.
kolbaska11 [484]
Gravitational attraction / field strength increases when closer; A light dependent resistor (LDR) can be used as a sensor to detect light intensity.
4 0
3 years ago
What is the flow rate of water in a pipe flowing full with an area of 0.3 m2 and velocity of 2.5 m/s?
sashaice [31]

Answer:

0.75 m³/s

Explanation:

Applying,

Q = vA.................... Equation 1

Where Q = flow rate of the water, v = velocity of the water, A = area of the pipe.

From the question,

Given: v = 2.5 m/s, A = 0.3 m²

Substitute these values into equation 1

Q = 2.5(0.3)

Q = 0.75 m³/s

Hence the flow rate of water in the pipe is 0.75 m³/s

4 0
2 years ago
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