Question

A 2.00 L flask is filled with propane gas (C3H8) at a pressure of 1.10 atm and a temperature of 258 K. What is the mass of propane in the flask?

Answer 1

Answer:

m = 4.58 g.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this problem is solved via the ideal gas equation:

$PV=nRT$

As we can calculate the moles of propane given the pressure, temperature and volume as shown below:

$n=\frac{PV}{RT} \\\\n=\frac{1.10atm*2.00L}{0.08206\frac{atm*L}{mol*K}*258K} \\\\n=0.104mol$

Finally, since the molar mass of propane is 44.1 g/mol, we calculate the mass by following the shown below mole-mass conversion factor:

$m=0.104mol*\frac{44.1g}{1mol}\\\\m= 4.58g$

Regards!