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mezya [45]
3 years ago
5

Why do the densities of most substances increase when temperature decreases?

Chemistry
2 answers:
Sonbull [250]3 years ago
7 0

Answer – Volume’s proportionality to temperature is direct.

Explanation-

As we know density is the mass of an object per unit volume of that object it depends on the volume and we also know that volume is dependent directly on temperature does. When temperature of something increases, then the volume of that object also increases. Because on heating the molecules start moving faster and faster movement of molecules need more space.

Hence the opposite happens when temperature decreases the volume and volume being inversely proportional to density causes and the density to increase in kinetic energy.  

vlada-n [284]3 years ago
6 0

This is because temperatures determine the kinetic energy of molecules of a substance, At lower temperatures the molecules have low kinetic energy hence the distance between molecules is not as large as when the kinetic energy is higher (because the molecules bombard less and with less kinetic energy). This means the substance can pack more molecules per volume at lower temperatures. The more the molecules per volume the higher the density.

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Verdich [7]

there is your answer

7 0
3 years ago
Read 2 more answers
Given the balanced equation: 2KClO3 -->2KCl + 3O2
RSB [31]

Answer:

Option a → 111.9 g

Explanation:

The reaction is this:

2KClO₃  →  2KCl  +  3O₂

2 moles of chlorate decompose to 2 moles of chloride and 3 moles of oxygen. Ratio is 2:2.

If I use 1.5 moles of chlorate I'll get the same moles of chloride by the decomposition.

Let's convert the moles to mass: 1.5 mol . 74.6 g / 1mol = 11.9 g

6 0
3 years ago
Balloon has a volume of 600-ml at temperature of 360 K. If the temperature of
Molodets [167]

Answer:

V₂ ≈416.7 mL

Explanation:

This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.

  • V₁ / T₁ = V₂ / T₂

where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.

The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,

  • V₁= 600 mL
  • T₁= 360 K
  • T₂= 250 K

Substitute the values into the formula.

  • 600 mL /360 K = V₂ / 250 K

Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.

  • 250 K * 600 mL /360 K = V₂ / 250 K * 250 K
  • 250 K * 600 mL/360 K = V₂

The units of Kelvin cancel, so we are left with the units of mL.

  • 250 * 600 mL/360=V₂
  • 416.666666667 mL= V₂

Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.

  • 416.7 mL ≈V₂

The volume of the balloon at 250 K is approximately 416.7 milliliters.

5 0
3 years ago
The reaction AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq) is a_________<br><br>reaction. please help
Paladinen [302]

Answer:

it's a precipitation reaction.

Explanation:

the solid produced is insoluble with water–making it a precipitate.

3 0
3 years ago
If a balloon containing 3000 L of gas at 39 C and 99 k Pa rises to an altitude where the pressure is 45.5 kPa and the temperatur
mihalych1998 [28]

Answer:

The new volume of the balloon will be 6046.28 L

Explanation:

Initial pressure (P1) = 99 kpa

initial volume (V1) = 3000 L

Initial temperature = 39 C = 39 + 273 = 312 K

Final pressure (P2) = 45.5 kpa

Final temperature = 16 C = 16 +273 = 289K

Final volume = ????

To calculate the final volume using the general gas equation

                  P1 V1 / T1  = P2 V2 / T2

make V2 the subject of the formular

                   V2 = 99000 ×3000× 289 / 45500×312

                   V2 = 85833000 /14196

                     V2 = 6046.28 litres

5 0
3 years ago
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