In reality, reactants don't have to react in perfect whole-numbers of moles. In a two-reactant synthesis reaction, usually one

Chemistry

1 answer:

Fofino [41]2 years ago

5 0

Answer:

srry i cant help u with this im so confuse like u just put all of it on there how would anybody answer tht!

?!Explanation:

You might be interested in

♦ O people, evidence has come to you from your Lord, and we have sent down to you a clear light ﴾[An-Nisa: 174].

Yuri [45]

Answer:

Qura'an is what makes my day, I read it every morning and it makes me relaxed. I love reading the Qura'an. Do dua for me because I hope I am gonna memorize it after I finish reading it with tajweed.

Explanation:

7 0

3 years ago

Read 2 more answers

The combustion of ethene in the presence of excess oxygen yields carbon dioxide and water: c2h4 (g) + 3o2 (g) → 2co2 (g) + 2h2o

meriva

Answer:

$\boxed{-267.5}$

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

$\Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}$

The equation for the reaction is

C₂H₄(g) + 3O₂(g) ⟶ 2CO₂(g) + 2H₂O(ℓ)

ΔS°/J·K⁻¹mol⁻¹ 219.5 205.0 213.6 69.9

$\Delta_{r} S^{\circ} = (2\times213.6 + 2\times69.9) - (1\times219.5 + 3\times205.0)\\\\= 567.0 - 834.5 = \boxed{-267.5 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}}$