1.596 grams is the mass of CuSO4 needed to prepare 100 ml solution of 0.1 M solution.
Explanation:
Data given:
Volume of the solution = 100 ml or 0.1 litre
molarity of the solution = 0.10 M
mass of CuS
= ?
atomic mass of CuS = 159.6 grams/mole
The mass will calculated by using the following relations:
number of moles = 
equation 1
molarity = 
equation 2
putting the value of number of moles in equation 2
molarity = 
mass = molarity x atomic mass x volume
mass = 0.1 x 0.1 x 159.6
= 1.596 grams
1.596 grams will form 100ml solution 0.1 M
In 1 mole of magnesium there are Avogadro's number of atoms are present.
Avogadro's number = 6.023 x 10²³
1 mole = 6.023 x 10²³ atoms
3.75 moles = 3.75 x 6.023 x 10²³
=2.26 x 10²⁴
So, in 3.75 moles of magnesium there are 2.26 x 10²⁴ atoms of magnesium are present.
4.7e^6 is how I would write it. You simply count in from the right side where the decimal is until you reach the point just before the 4.
it has four significant figures.
According to the Aufbau principle, , electrons orbiting one or more atoms fill the lowest available energy levels before filling higher levels (e.g., 1s before 2s).
