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2 years ago

Annalise invested $3,300 in an account paying an interest rate of 2.8% compounded monthly. Assuming

Mathematics

1 answer:

Artist 52 [7]2 years ago

4 0

Answer:

$4,881.56

Step-by-step explanation:

The future value formula is ...

FV = P(1 +r/n)^(nt)

where principal P is invested at annual rate r compounded n times per year for t years.

You have P=3300, n=12, r=0.028, t=14, so the future value is ...

FV = $3300(1 +0.028/12)^(12·14) = $4881.56

There would be $4881.56 in the account after 14 years.

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WILL MARK BEST ANSWR BRAINLIEST!!!!!!

Oksana_A [137]

- 1/3 - 1 2/3 = - 2

When subtracting two negatives you add the two numbers together.

5 0

3 years ago

Read 2 more answers

Please answer this in two minutes

alisha [4.7K]

Answer:

WX = 7.9

Step-by-step explanation:

By applying tangent rule (law of tan) in the given right triangle WXY.

tan(W) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

tan(27)° = $\frac{\text{XY}}{\text{WX}}$

0.509525 = $\frac{4}{\text{WX}}$

WX = $\frac{4}{0.509525}$

WX = 7.85

WX ≈ 7.9

Therefore, length of side WX is 7.9 units.

3 0

3 years ago

Find the linear approximating polynomial for the following function centered at the given point a.point a. b. Find the quadratic

ZanzabumX [31]

Answer:

$(a)L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})\\(b)Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2\\(c)L(-0.23\pi)=-0.6626\\Q(-0.23\pi)=-0.6613$

Step-by-step explanation:

Given the function:

$f(x)=sin x, a=-\frac{\pi}{4}$

(a)Linear approximating polynomial

$L(x)=f(a)+f'(a)(x-a)\\f(a)=sin(-\frac{\pi}{4})=-\frac{\sqrt{2} }{2}\\f'(x)=cos x, a=-\frac{\pi}{4}\\f'(a)=cos (-\frac{\pi}{4})=\frac{\sqrt{2} }{2} \\Therefore:\\L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x-(-\frac{\pi}{4}))\\L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})$

(b)Quadratic approximating polynomial

$Q(x)=L(x)+\frac{1}{2}f''(a)(x-a)^2\\f''(x)=-sin(x), \\f''(a)=-sin(-\frac{\pi}{4})=\frac{\sqrt{2} }{2}\\Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2$

(c)When $x=-0.23\pi$

Using Linear Approximation polynomial

$L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})\\L(-0.23\pi)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(-0.23\pi+\frac{\pi}{4})\\L(-0.23\pi)=-0.6626$

Using the Quadratic approximating polynomial

$Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2\\Q(-0.23\pi)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(-0.23\pi+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(-0.23\pi+\frac{\pi}{4})^2=-0.6613$

4 0

3 years ago

1) Which rate is the lowest price?

jeyben [28]

1. 2.5/5 = .50
2.4/6 = .40 Lowest price
3.0/6 = .50
2.4/4 = .60

2. 150/6 = 25 Equivalent
50/1.5 = 33.33
100/3.8 = 26.32
75/3 = 25 Equivalent

3. 30/1 = 30
90/2 = 45
180/3 = 60 Fastest
240/6 = 40

3 0

3 years ago

Will the value of the expression 20−x increase, decrease, or stay the same as x increases? Explain.

asambeis [7]

Answer:

Step-by-step explanation:

Given the expression 20 - x.

The value of x determines if the value of the expression would increase, decrease or stay the same. When the value of x decreases, the value of 20 - x increases. When the value of x increases, the value of 20 - x decreases. And when the value of x does not change, 20 - x remains the same.

When greater values of x is subtracted from 20, you will have lower value left. Therefore, as x increases, the value of the expression 20 - x will decrease.

7 0

3 years ago