Answer is: Keq = [CO₂].
Balanced chemical reaction: CaCO3(s) ⇄ CaO(s) + CO₂(g).
The equilibrium constant (Keq) is a ratio of the concentration of the products to the concentration of the reactants.
Pure liquids (shown in chemical reactions by appending (l) to the chemical formula) and solids (shown in chemical equations by appending (s) to the chemical formula) not go in to he equilibrium constant expression, only gas state (shown in chemical reactions by appending (g) to the chemical formula) reactants and products go in to the equilibrium constant expression.
Answer:
D
Explanation:
Because the other answers can not to be considered to be chemical properties.
Chemical means that the after the reaction the checal properties have changed in a way that it can no longer be called the same ad befor. In short, it can not be undone.
Burning a match is irriversable, meaning you can never go back to the previous situation because the chemical compounds have changed (dramatically).
Melted ice can be frozen again. Steam (evaporated water) can condensate to water which can be heated and can boil again. The chemical contents remain H2O.
Answer : The volume of 
is 14.784 L.
Solution : Given,
Mass of Aluminium = 6 g
Molar mass of Aluminium = 27 g/mole
First we have to calculate the moles of aluminium.
Moles of Al = 
The given balanced reaction is,
From the reaction, we conclude that
2 moles of Al react with the 6 moles of
0.22 moles of Al react with 
of
At STP, 1 mole contains 22.4 L volume
As, 1 mole of contains 22.4 L volume of
0.66 moles of contains 
volume of
Therefore, the volume of is 14.784 L.
Answer:
Goal: to propose a strategy to mitigate carcinogenic dyes present in wastewater.
Explanation:
Hello,
Short-term: Based on my interest about the treatment of carcinogenic effluents in the dyes industry, I'm planning to develop a research about how fast microorganisms could decompose such dyes in order to provide pure water-composed outlet streams. For now, I can suggest that they could work as long as they grow in a simulated dye-rich environment.
Medium-term: In such a way, the subsequent plan is to set up the reaction scheme and the reactor design stage for this bioprocess by running several test in order to collect the experimental data to back up the proposed mathematical model.
Long-term: Finally, the start-up of the whole process starting by the inlets and operation conditions, continuing by the innermost sub processes to decompose the dye and the subsequent adaptation of the outlet streams to produce drinkable water, will be carried out in order to help the environment and living things that are highly affected by those dyes.
Best regards.
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
