Solve the system of equations 6x+3y=12 and 5x+y=7
2 answers:
6x+3y = 12 Solving for x 3(2x+y)=12 2x+y=12/3 2x+y=4 2x=4-y X=4-y/2
Answer:
x = 1; y = 2
Step-by-step explanation:
<u>To find x:</u>
Multiply (5x+y=7) by 3 to get the y's in both equation the same, and you will get 15x+3y=21.
Now the y's cancel out. Subtract the remaining equations: (15x=21) - (6x=12) and you get 9x = 9. Divide everything by 9 and you get <u>x=1 </u>.
<u>To find y:</u>
You can substitute 1 for x in either equation. I will use (5x+y=7).
Substitute the 1 for x: 5(1)+y=7
Simplify: 5+y=7
Put like terms on the same side by subtracting 5 from both sides: <u>y=2 </u>
<u> </u>
Check:
6(1) + 3(2) = 12
6 + 6 = 12
12 = 12 - this is right
5(1) + (2) = 7
5 + 2 = 7
7 = 7 - this is right
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Answer:
9
Step-by-step explanation:
Percent error=|
| times 100
(note the || is absolute value, means that whatever the result is inside, it is made positive)
predicted value=261
actual value=293
subsitute
percent error=|
| times 100
so using pemdas
do parenthasees first
|
|
|-0.12|
absolute value
0.1226
time 100
0.1226 times 100=12.26
answer is 12.26%
answer is B