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gizmo_the_mogwai [7]
2 years ago
9

The force of gravity pulls down on your school with a total force of 400,000 newtons. The force of gravity pulling down on your

school would be exactly twice as much if your school: a Had twice as much mass b Was twice as tall c Had twice as much volume d Covered twice as much area
Physics
1 answer:
gizmo_the_mogwai [7]2 years ago
7 0

Answer: a Had twice as much mass

Explanation:

The data that we have is:

"The force of gravity pulls down on your school with a total force of 400,000 newtons. "

First, remember that, by the second Newton's law that:

F = a*m

F = force

a = acceleration

m = mass

In the case of the gravitational force, the gravitational acceleration is a constant: a = 9.8m/s^2

Then, if we want to have twice as much force the only thing that we can change in the equation is the mass:

Then if the initial force is written as:

F = a*m

twice as much that force is written as:

2*F = a*x

x is a variable that represents the new mass.

We know that F = a*m

2*F = 2*a*m

2*a*m  = a*x

2*m = x

Then, if we want to have twice as much force, we should have twice as much mass.

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Answer:

Approximate height of the building is 23213 meters.

Explanation:

Let the height of the building be represented by h.

0.02 radians = 0.02 × \frac{180^{o} }{\pi }

                     = 0.02 x (180/\frac{22}{7})

0.02 radians  = 1.146°

10.5 km = 10500 m

Applying the trigonometric function, we have;

Tan θ = \frac{opposite}{adjacent}

So that,

Tan 1.146° = \frac{h}{10500}

⇒ h = Tan 1.146° x 10500

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      = 23212.77

h = 23213 m

The approximate height of the building is 23213 m.

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2 years ago
Two particles collide, one of which was initially moving and the other initially at rest. Is it possible for both particles to b
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Answer:

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