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gizmo_the_mogwai [7]
3 years ago
9

The force of gravity pulls down on your school with a total force of 400,000 newtons. The force of gravity pulling down on your

school would be exactly twice as much if your school: a Had twice as much mass b Was twice as tall c Had twice as much volume d Covered twice as much area
Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Answer: a Had twice as much mass

Explanation:

The data that we have is:

"The force of gravity pulls down on your school with a total force of 400,000 newtons. "

First, remember that, by the second Newton's law that:

F = a*m

F = force

a = acceleration

m = mass

In the case of the gravitational force, the gravitational acceleration is a constant: a = 9.8m/s^2

Then, if we want to have twice as much force the only thing that we can change in the equation is the mass:

Then if the initial force is written as:

F = a*m

twice as much that force is written as:

2*F = a*x

x is a variable that represents the new mass.

We know that F = a*m

2*F = 2*a*m

2*a*m  = a*x

2*m = x

Then, if we want to have twice as much force, we should have twice as much mass.

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1.15) What distance will 650 joules of work move a box weighing 50 newtons?​
son4ous [18]

Answer:

The answer is 13 however make sure if they ask for a certain measurement like meter answer it by saying 13 meters.

Explanation:

This basically turns into basic algebra if you know the formula for work. The formula for work is W=F*d  

Here are the variables that you know 650J=50N*d so you need d.

All you do is divide 650J by 50N and you get a total of 13 (meters since I don't know what they want you to put it in).

6 0
3 years ago
Ví dụ 1 : Hai vật xuất phát từ A và B cách nhau 400m chuyển động cùng chiều theo hướng từ A đến B. Vật thứ nhất chuyển động đều
Mashcka [7]

Answer:

Ví dụ 1 : Hai vật xuất phát từ A và B cách nhau 400m chuyển động cùng chiều theo hướng từ A đến B. Vật thứ nhất chuyển động đều từ A với vận tốc 36km/h. Vật thứ hai chuyển động đều từ B với vận tốc 18km/h. Sau bao lâu hai vật gặp nhau ? Gặp nhau chỗ nào

8 0
3 years ago
A granite monument has a volume of 25,365.4 cm3. The density of granite is 2.7 g/cm3. Use this information to calculate the mass
LiRa [457]
As density = mass/volume

So

Mass = density *volume

Mass = 25,365.4 * 2.7 = 68,486.58 g

<span>Mass of the granite monument to the nearest tenth = 68,485.6 g</span>

5 0
3 years ago
What is the density of 53.4 wt queous naoh solution if 16.7 ml of the solution diluted to 2.00 l gives 0.169 m naoh?
vampirchik [111]

The density of 53.4 wt aqueous NaOH solution is 0.809 g/ml

Given data:

  • The mass percent of NaOH is 53.4.
  • Volume of NaOH diluted is 16.7 ml.
  • The volume of diluted solution is 2.00 L =2000 ml.
  • Concentration of diluted solution is 0.169 M.

First, we find the initial concentration of NaOH by using the following formulae,

M₁V₁ = M₂V₂

Where,

M₁ is the initial molarity of NaOH

M₂ is the molarity after dilution

V₁ is the initial volume of NaOH

V₂ is the final volume after dilution.

Substituting the values,

M₁ × 16.7 ml = 0.169 M × 2000 ml,

M₁ =  \frac{0.169 M *2000 ml}{16.7 ml}

M₁ = 20.2 M.

Thus, the initial concentration of NaOH is 20.2 M.

we know, 1 M solution contains 1 mol of substance present in 1 L solution,

Thus, 20.2 M solution will have 20.2 mols of NaOH.

Now, we can find the mass of NaOH by using the number of moles and molar mass.

  • molar mass of NaOH is 40 g/mol.

Mass = no. of moles × molar mass

= 20.2 mol × 40 g/mol

= 808 g.

Thus, the mass of NaOH is 808g.

53.4 wt of NaOH means 53.4 g of NaOH in a 100 g solution,

Thus, 808 g of NaOH will be present in ,

⇒ \frac{53.4 g NaOH}{100 g solution} = \frac{808 g NaOH}{x g solution}

⇒ 1513.1 g

Now, Convert the grams of NaOH to milliliters, using the density of NaOH at room temperature.

  • The density of NaOH at room temperature is 1.515 g/ml,

Density = \frac{mass}{volume}

⇒ 1.515 g/mol = \frac{1513.1 g}{volume}

⇒ volume = \frac{1513.1 g}{1.515 g/mol}

⇒ volume = 998.7 ml.

Thus, the volume of NaOH is 998.7 ml.

Hence, we know,

  • the mass of NaOH is 808 g
  • the volume of NaOH is 998.7 ml

Substituting the values,

Density = 808 g / 998.7 g/ml

⇒ Density = 0.809 g/ml

Thus, the density of 53.4 wt aqueous NaOH is 0.809 g/ml.

To learn more about Density here

brainly.com/question/15164682

#SPJ4

3 0
2 years ago
Ở nhiệt độ không đổi, dưới áp suất 10^4 Pa l, một lượng khí có thể tích 10l. Tính thể tích lượng khí đó dưới áp suất 5.10^4 Pa
gtnhenbr [62]

Answer:

Thể tích cuối cùng, V2 = 2 L

Explanation:

Cho các dữ liệu sau đây;

Khối lượng ban đầu = 10 L

Áp suất ban đầu = 10⁴ = 10000 Pa

Áp suất cuối cùng = 5 * 10⁴ = 50000 Pa

Để tìm tập mới hoặc tập cuối cùng, chúng ta sẽ sử dụng định luật Boyle;

Để tìm tập mới V2, chúng tôi sẽ sử dụng định luật Boyles.

Boyles phát biểu rằng khi nhiệt độ của khí lý tưởng được giữ không đổi, áp suất của khí tỉ lệ nghịch với thể tích mà khí chiếm giữ.

Về mặt toán học, định luật Boyles được đưa ra bởi;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Thay vào phương trình, ta có;

10000 * 10 = 50000V_{2}

100000 = 50000V_{2}

V_{2} = \frac {100000}{50000}

V_{2} = 2

Thể tích cuối cùng, V2 = 2 L

6 0
3 years ago
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