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3 years ago

Can you please help me??

Mathematics

1 answer:

Sergio039 [100]3 years ago

4 0

Answer:

your picture has 2 main points

Step-by-step explanation:

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List two pairs of fractions with a product of 6/40

puteri [66]

Answer:

The product of two fractions can be calculated as follows:

$\frac{a}{b}\cdot \frac{c}{d}=\frac{a \cdot c}{b \cdot d}$

So, the numerator is the product of the numerators of the two fractions, and the denominator is the product of the denominators of the two fractions.

In this problem, we know that the product is 6/40, so:

$ac = 6\\bd = 40$

This means:

$c=\frac{6}{a}\\d=\frac{40}{b}$

So we just need to find 2 pairs of numbers a, b to make c and d integers.

The first choice we use is:

a = 3

b = 2

So we get:

$c=\frac{6}{3}=2\\d=\frac{40}{2}=20$

So the first pair of fractions is

$\frac{3}{2},\frac{2}{20}$

The second choice we use is:

a = 2

b = 10

So we get:

$c=\frac{6}{2}=3\\d=\frac{40}{10}=4$

So the second pair of fractions is

$\frac{2}{10},\frac{3}{4}$

8 0

3 years ago

Solve. 3n-7+2n=8n+11

Bezzdna [24]

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Question:
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3n - 7 + 2n = 8n + 11

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Combine like terms:
------------------------------------
5n - 7 = 8n + 11

------------------------------------
subtract 8n from both sides:
------------------------------------
-3n - 7 = 11

------------------------------------
Add 7 to both sides
------------------------------------
-3n = 18

------------------------------------
Divide by -3 on both sides:
------------------------------------
n = -6

------------------------------------
Answer: n = -6
------------------------------------

5 0

3 years ago

Prove that (n+5)^2-(n+3)^2 is a multiple of 4 for all positive integer values of n

hodyreva [135]

Answer:

Proved

Step-by-step explanation:

Given

$(n+5)^2-(n+3)^2$