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ruslelena [56]
3 years ago
5

How can you tell how reactive an element is?

Chemistry
1 answer:
astraxan [27]3 years ago
6 0
Well, on a period table for metals, reactivity increases down a group & from right to left
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Question 2
Pavel [41]
Tearing paper, Physical Change
6 0
3 years ago
Which characteristics affect ocean water’s temperature? Check all that apply. depth location mass salinity waves
RideAnS [48]

Answer:

Depth and location affect ocean water’s temperature.

Explanation:

The main source of heat for the oceans is solar radiation. That is, water is basically heated by the radiation of the Sun, which transmits energy to the surface. The ocean absorbs this energy and stores it. Seawater has high caloric capacity. This means that more energy and more time is needed to change or increase the water temperature, compared to the air temperature. Similarly, once the ocean heats up, it takes a long time for the water to completely release or lose that heat.

The temperature decreases to greater depth, because the amount of solar radiation is reduced. On the contrary, it is greater where there is greater energy or heat content.

The closer a place is to the equator, the solar energy will affect more vertically and with more intensity on it, so the warmer the temperatures will be. The further that point of the equator is found, the solar energy will reach it with a smaller angle. And if the point is near the poles, the sun's rays will arrive at a very small angle. This causes the temperature of the water of the oceans to vary depending on the earth's latitude, being higher in areas close to the equator and the tropics, and colder the closer to the poles or the further away from the temperate zones.

3 0
3 years ago
Read 2 more answers
Could someone please care to explain what the answer is
polet [3.4K]

Calculate the percentage composition of Ca(MnO4)2.

<u>Firstly, we see how many atoms are there for each element in the formula</u>.

Ca= 1 atom

Mn= 2 atoms

O= 8 atoms

<u>Next, we are going to consult our periodic table for the atomic mass of each element.</u>

Ca= 40

Mn= 55

O= 16

Then, we have to find the molar mass for the compound..

Here is the formula for calculating molar mass of an element:

Molar Mass= ( no. of atoms of the element × atomic mass of the element)

Now, we have to calculate the atomic mass of the compound. So using the molar mass formula for an element, we calculate the molar mass for each element then we sum up their molar masses to get the compounds molar mass.

Molar mass (Ca)= 1× 40

(Ca)= 40

Molar mass (Mn)=2×55

(Mn)= 110

Molar mass (O)= 8×16

(O)= 128

Now: Molar mass( compound)= (Ca)+(Mn)+(O)

= 40+ 110 128

= 278

This is everything we need to calculate our percentage composition for each element..

* The example says to find the percentage composition for Ca. So we only find for Ca, Which is already done using the formula and the answer is 14.39%.

To prove that your answer is correct, find the percentage composition for Mn and O as well. Then you add up their percentage compositions.

If you do and you get 100 as your answer, then your percentage compositions are correct.

Why don't you try finding the percentage composition for Mn and O, then add up all the three percentage compositions. If you 100 as their sum, then your percentage composition for each of the elements are correct.

6 0
3 years ago
Which molecule among these is a polar
Alika [10]
Can you upload the picture please so i can help
5 0
3 years ago
What factors play a role in the rate at which molecules like O₂ and CO₂ can diffuse?
nadezda [96]

Answer:

The correct answer is b the magnitude of the concentration gradient of the molecule.

Explanation:

Dffusion is one of most important membrane transport process that allow several molecules such as gases oxygen and carbon dioxide to pass directly across the plasma membrane.The is no involvement of  carrier proteins or ion channels during passive diffusion.

    During passive diffusion molecules are transported along their concentration gradient that means from the region of high concentration to region of low concentration,until the concentration of both regions become same.

8 0
3 years ago
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