The given question describes a right triangle with with one of the angles as 20 degrees and the side adjacent to the angle 20 degrees is of length 5,000 feet. We are looking for the length of the side opposite the angle 20 degrees.

Let the required length be x, then

$\tan{20^o}=\cfrac{opp}{hyp}=\cfrac{x}{5,000}\\ \\ \Rightarrow x=5,000\tan{20^o}=1,819.85$

Therefore, the height of the airplane above the tower is 1,819.85 feet.

8 0

3 years ago

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Solve this equation: 4y + 228 = 352. A. y = 31 B. y = – 31 C. y = 3 D. y = 145

V125BC [204]

To let the variable alone you can follow these steps: 1) subtract 228 from both sides 2) divide both sides by 4. This is the solution: 1) 4y + 228 - 228 = 352 - 228 => 2) 4y = 124 => 3) (4y)/4 = 124/4 => 4) y = 31. Then, the answer is the option A. y = 31.

3 0

3 years ago

Mr. Witherspoon's fifth grade class was on the

enot [183]

A triangle do it out on paper

4 0

3 years ago