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Kamila [148]
3 years ago
13

Are the ratios 16:8 and 4:2 equivalent?

Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0
Yes
16/4 is 4
8/2 is 4 as well
Making them equivalent
You might be interested in
triangle jkl is similar to triangle tuv. find the missing side length of triangle tuv. JK=10in JL=8in KL=13in TU=7.5 UV=9.75 fin
hammer [34]

Answer:

TV=6 inch

Step-by-step explanation:

If Triangle JKL is similar to Triangle TUV, the following ratio applies.

\dfrac{JK}{TU}= \dfrac{KL}{UV}=\dfrac{JL}{TV}\\$JK=10in.,  JL=8in.,  KL=13in.,  TU=7.5.,  UV=9.75\\\dfrac{10}{7.5}= \dfrac{13}{9.75}=\dfrac{8}{TV}\\$Picking any two equal ratios\\ \dfrac{13}{9.75}=\dfrac{8}{TV}\\$Cross multiply\\13*TV=8*9.75\\TV=8*9.75 \div 13\\$TV=6 inch

7 0
3 years ago
What is (3.1x10^5)(2.2x10^7) in scientific notation?
aivan3 [116]

The scientific notation:

a\cdot 10^k where 1\leq a < 10 and k\in\mathbb{Z}

(3.1\cdot10^5)(2.2\cdot10^7)=(3.1)(2.2)(10^5\cdot10^7)\\\\=6.82\cdot10^{5+7}=6.82\cdot10^{12}

8 0
3 years ago
Read 2 more answers
Find the greatest common factor between 18 and 60? Help me or I die.....Jk help me plz​
lidiya [134]
6,3,2,1 there is your answer bud have a great day
4 0
3 years ago
Read 2 more answers
Please I want the area and perimeter of this shape!!<br> With steps and explanation please!!
worty [1.4K]

For perimeter you will add each side together so

8ft+22ft+12ft+16ft=58

So your perimeter is 58ft.

For area your going to divide the shape into 2 to get the area as this is an irregular shape, so

Base 1+base2x height / by 2

22+8 x4/2

30x4/2

120/2

60

If you’re wondering how I got 4 I subtracted 16 with 12 to know what the height was. Good luck!!

7 0
3 years ago
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and
Ksju [112]

Answer:

A) 1

B) 1

C) 0

Step-by-step explanation:

The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. Suppose that a random sample of n = 49 customers is observed. Find the probability that the average time waiting in line for these customers is A) Less than 10 minutes B) Between 5 and 10 minutes C) Less than 6 minutes

We solve this question using the z score formula

z = (x-μ)/σ/√n, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

n = number of random samples

A) Less than 10 minutes

x < 10

z = 10 - 8.2/ 1.5 / √49

z = 8.4

P-value from Z-Table:

P(x<10) = 1

B) Between 5 and 10 minutes

For x = 5 minutes

z = 5 - 8.2/ 1.5 / √49

z = -14.93333

P-value from Z-Table:

P(x = 5) = 0

For x = 10 minutes

z = 10 - 8.2/ 1.5 / √49

z = 8.4

P-value from Z-Table:

P(x = 10) = 1

The probability that the average time waiting in line for these customers is between 5 and 10 minutes

P(x = 10) - P(x = 5)

= 1 - 0

= 1

C) Less than 6 minutes

x < 6

z = 6 - 8.2/ 1.5 / √49

z = -10.26667

P-value from Z-Table:

P(x<6) = 0

6 0
3 years ago
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