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mash [69]
3 years ago
5

A truck traveling at a velocity of 33m/s comes to a halt by decelerating at 11m/s^2. How far does the truck travel in the proces

s of stopping. identify known variables such as V, V0, a, t, and delta x.
Physics
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

<u><em>The truck was moving 16.5 m/s during the time it took to stop, which was 3 seconds. </em></u>

  • <u><em>Initial velocity = 33 m/s</em></u>
  • <u><em>Final velocity = 0 m/s</em></u>
  • <u><em>Average velocity = (33 + 0) / 2  m/s = 16.5 m/s</em></u>

Explanation:

  1. <u><em>First, how long does it take the truck to come to a complete stop?</em></u>
  1. <u><em>( 33 m/s ) / ( 11 m / s^2 ) = 3 seconds</em></u>
  1. <u><em>Then we can look at the average velocity between when the truck started decelerating and when it came to a complete stop. Because the deceleration is constant (always 11m/s^2) we can use this trick.</em></u>
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4 years ago
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In reading the instruction manual that came with your garagedoor opener, you see that the transmitter unit in your car produces
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0.09221 V/m

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Intensity of a wave is given by

I=\frac{P}{4\pi r^2}\\\Rightarrow I=\frac{250\times 10^{-3}}{4\pi \times 42^2}\\\Rightarrow I=1.12779\times 10^{-5}\ W/m^2

Intensity is also given by

I=\frac{E_0^2}{2\mu_0 c}\\\Rightarrow E_0=\sqrt{I2\mu_0 c}\\\Rightarrow E_0=\sqrt{1.12779\times 10^{-5}\times 2\times 4\pi \times 10^{-7}\times 3\times 10^8}\\\Rightarrow E_0=0.09221\ V/m

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4 years ago
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3 years ago
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Answer:

m = 17.87 kg

Explanation:

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m = m_1 + m_2

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3 0
3 years ago
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