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exis [7]
3 years ago
15

"Comparing microwaves and visible light, which of the following is true? 1. Microwaves have higher frequency, same speed, and lo

nger wavelength than visible light. 2. Microwaves have lower frequency, same speed, and longer wavelength than visible light. 3. Microwaves have lower frequency, slower speed, and longer wavelength than visible light. 4. Microwaves have lower frequency, faster speed, and shorter wavelength than visible light."
Physics
1 answer:
Alex17521 [72]3 years ago
6 0

Answer:

2. Microwaves have lower frequency, same speed, and longer wavelength than visible light.

Explanation:

Microwaves are a form of electromagnetic radiation. Most people are familiar with this type of waves because they are used in microwave ovens. When compared to visible light, microwaves have lower frequency, same speed and longer wavelength than visible light. The prefix "micro" is used to indicate that microwaves are smaller (shorter wavelengths) than radio waves.

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the two rotating systems shown in the figure differ only in that the two identical movable masses are positioned at different di
svetoff [14.1K]

Answer: the block at the right lands first

Explanation:

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3 years ago
Hi i need answers for this. Thank you!! this is also really important and is due tomorrow at 9am!!
Allushta [10]

Answer:

You're four sentences should include about how the roller coaster has the most potential energy at the top of the track, and the opposing energy, "kinetic" has the most kinetic energy when going down the hill.

Explanation:

Kinetic - In-Motion.

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3 years ago
A force of 120.0 N is applied to a 3.00 kg block. What is the average acceleration of the block?
kirza4 [7]

Explanation:

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6 0
3 years ago
A person holds a rifle horizontally and fires at a target. The bullet leaves the muzzle of the rifle with a velocity of 460 m/s.
Trava [24]

Answer:

the distance travelled from the bullet to the target  is 391m

Explanation:

Hello! To solve this exercise we must follow the following steps.

1. the bullet travels with constant speed which means that the distance traveled to the target is given by the following equation

X=(V1)(T1)

T1=\frac{X}{V1} =\frac{x}{460}

where

X=target distance

V1=bullet speed=460m/s

T1=

time it takes for the bullet to reach the target

2. The distance the sound travels is given by the following equation (it is the same as the distance from the person to the target)

X=(V2)(T2)

T2=\frac{X}{V2} =\frac{x}{340}

X=

target distance

V2= speed of sound=340m/s

T2=   time it takes the sound of the Bullet to return.

3. The total time it takes for the person to hear the bullet(T=2s) is the sum of the time it takes for the bullet to reach the target, plus the time it takes for the sound to reach the person, with the above we infer the following equation

T=T1+T2

2=T1+T2

4. Finally we use the equations found in step 1 and 2 to find the distance traveled using algebra.

2=\frac{x}{340}+\frac{x}{460} \\x(\frac{1}{340} +\frac{1}{460} )=2\\\ X= \frac{2}{(\frac{1}{340} +\frac{1}{460} )} \\\\x=391m

the distance travelled from the bullet to the target  is 391m

3 0
3 years ago
True or false<br> two different notes can have the same fundamental frequency
Grace [21]

Answer:

true:)

Explanation:

3 0
3 years ago
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