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exis [7]
3 years ago
15

"Comparing microwaves and visible light, which of the following is true? 1. Microwaves have higher frequency, same speed, and lo

nger wavelength than visible light. 2. Microwaves have lower frequency, same speed, and longer wavelength than visible light. 3. Microwaves have lower frequency, slower speed, and longer wavelength than visible light. 4. Microwaves have lower frequency, faster speed, and shorter wavelength than visible light."
Physics
1 answer:
Alex17521 [72]3 years ago
6 0

Answer:

2. Microwaves have lower frequency, same speed, and longer wavelength than visible light.

Explanation:

Microwaves are a form of electromagnetic radiation. Most people are familiar with this type of waves because they are used in microwave ovens. When compared to visible light, microwaves have lower frequency, same speed and longer wavelength than visible light. The prefix "micro" is used to indicate that microwaves are smaller (shorter wavelengths) than radio waves.

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52m/s is the answer because before it was gonna accelerate it was 52 m/s
6 0
3 years ago
What makes a model not useful?
lina2011 [118]
Answer is b hope this helps
8 0
2 years ago
The circuits, P and Q, show two different ammeter-voltmeter methods of measuring resistance. Suppose the ammeter has a resistanc
qaws [65]

Answer:

Uncorrected values for

For circuit P

R = 2.4 ohm

For circuit Q

R = 2.4 ohm

Corrected values

for circuit P

R = 12 OHM

For circuit Q

R = 2.3 ohm

Explanation:

Given data:

Ammeter resistance 0.10 ohms

Resister resistance 3.0 ohms

Voltmeter read 6 volts

ammeter reads 2.5 amp

UNCORRECTED VALUES FOR

1) circuit P

we know that IR =V

R = \frac{6}{2.5} - 2.4 ohm

2) circuit Q

R = 2.4 ohm as no potential drop across ammeter

CORRECTED VALUES FOR

1) circuit p

IR = V

\frac{3R}{R+3} \times 2.5 = 6

R= 12 ohm

2) circuit Q

I\times (R+0.1) =V

R+0.1 =\frac{6}{2.5}

R = 2.3 ohm

5 0
3 years ago
A small sphere with mass 1.5g hangs by a thread between two parallel vertical plates 5cm apart. The plates are insulating and ha
kondaur [170]

The tralational equilibrium condition allows finding that the electric potential is   V = 4.8 10¹¹ V

Given parameter

  • The mass m = 1.5 g = 1.15 10-3 kg
  • The charge on the sphere q = 8.9 10-16 C
  • Plate spacing d = 5 cm = 5.00 10-2 m

To find

  • The potential difference

Newton's second law states that the force is proportional to the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it establishes the condition for the equilibrium of the bodies

          ∑ F = 0

Where the bold indicate vector and F is the force

To use this equation we must fix a reference system with respect to which to carry out the decomposition and measurements of the forces; let's fix a system with the horizontal x axis and the vertical y axis, in the attachment I could see a free body diagram.

x- axis

     Fe - Tₓ = 0

     Fe = Tₓ

y-axis

     T_y - W = 0

     W = T_y

     mg = T_y

The electric force is

      Fe = q E = q V / d

let's use trigonometry to decompose the stress

     cos 30 =  T_y / T

     sin 30 = Tₓ / T

      T_y = T cos 30

      Tₓ = T sin 30

We substitute

        q V / d = T sin 30

        mg = T cos 30

It's solve the system of equations

         \frac{q \ V}{d \ m g} = tan 30

         V = \frac{d \ mg }{ q}\ tan \  30

It's calculate

         V = \frac{5.00 \ 10^{-2} 1.5 \ 10^{-3} \ 9.8}{ 8.9 10^{-16} } \ tan \ 30

         V = 4.768 10¹¹ V

In conclusion, using the equilibrium condition, we could find that the electric potential is V = 4.8 10¹¹ V

Learn more about equilibrium condition here:

brainly.com/question/1967702

7 0
2 years ago
In the parallel circuit, is the current constant throughout the circuit, or does it vary?
Ber [7]
The current in a parallel circuits is not constant throughout the circuit. It varies in each path of a parallel circuit. The components that is place across each other have the same voltage in a parallel circuit. Remember, V=RI.
8 0
2 years ago
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