Answer: 568g/mol
Explanation:
It should be noted that there are 40 atoms of carbon in lycopene.
Since mass of 1 carbon = 12g/mol
Mass of 40 carbon atoms = 40 × 12g/mol = 480g/mol
Let the molar mass of lycopene be represented by x.
Therefore the molar mass of carbon = x × mass percent of carbon in lycopene
x × 84.49% = 480g/mol
x × 0.8449 = 480g/mol
x = 480/0.8449
x = 568g/mol
The molar mass of lycopene is 568g/mol
The reactant in a chemical reaction that limits the amount of product that can be formed. The reaction will stop when all of the limiting reactant is consumed
A reaction between acid and base to form water and salt is known as neutralization reaction. It is a double replacement reaction.
The reaction between 
and 
will be:
The balanced reaction is:
Volume of = 28 mL (given)
Since, 1 L = 1000 mL
So, 28 mL = 0.028 L
Molarity of = 5.4 M (given)
Molarity = 
-(1)
Substituting the values in equation (1):
From the balanced reaction between and , 2 moles of reacts with 1 mole of .
Molar mass of = 84.007 g/mol
Mass of needed:
= 
Hence, the required amount of is .
