I’m pretty sure he could only make 1 rectangle with 5cm because it’s an odd number which means he couldn’t stack them on top of each other evenly like he could with the 6cm rectangles, so he’d only be able to line them up next to each other and that’s it (I hope that’s right; sorry if it’s not but it makes sense to me lol)

8 0

3 years ago

Find the value of x. 16 40° D (Round to the nearest tenth as needed.)

dsp73

Answer:

Step-by-step explanation:

3 0

2 years ago

Assume that the weights of spawning Chinook salmon in the Columbia river are normally distributed. You randomly catch and weigh

s344n2d4d5 [400]

Answer: The point estimate for the mean weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample $(\overline{x})$ = 31.2 pounds .

Step-by-step explanation:

The weights of spawning Chinook salmon in the Columbia river are normally distributed.

Given : The mean weight from your sample is 31.2 pounds with a standard deviation of 4.4 pounds.

The point estimate for the mean $(\mu)$ weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample $(\overline{x})$ i.e. is 31.2 pounds because the best point estimate for population mean is the sample mean. [in normal distribution]

8 0

3 years ago

The quotient of w and 10 is equal to 7

Verdich [7]

Answer:

Step-by-step explanation:

6 0

3 years ago