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Oxana [17]
3 years ago
14

The diagram illustrates the water cycle.

Chemistry
2 answers:
castortr0y [4]3 years ago
8 0

Answer:

The Answer is Precipitation

Explanation:

Look it up on and then also got it right on the Unit Test and the Quiz.

Amiraneli [1.4K]3 years ago
3 0

Answer:

precipitation

Explanation:

trust me ............................

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Write this in a word and skeleton equation:
DiKsa [7]

Answer:

Write this in a word and skeleton equation:

Solid silver chloride and an aqueous solution of nitric acid are produced when a solution of silver nitrate is reacted with a solution of hydrochloric acid.

Explanation:

6 0
2 years ago
) Calculating Heat from Thermochemical Equations
SIZIF [17.4K]

A combustion reaction is a reaction that reacts in the presence of oxygen molecules. Methane will release -3115 kJ/mol of heat.

<h3>What is a combustion reaction?</h3>

A combustion reaction includes the reaction between the chemical reactant and oxygen molecule to produce the product. The combustion reaction between methane and oxygen is given as:

CH₄(g) + 2O₂ (g) → CO₂(g) + 2H₂O (l), ΔH = -890 kJ/mol

The stoichiometry coefficient from the reaction gives 1 mole of methane releases -890 kJ/mol enthalpy.

So, 3.5 moles methane will release = 3.5 × -890 = -3115 kJ/mol

Therefore, -3115 kJ/mol of heat is released.

Learn more about combustion reaction here:

brainly.com/question/27823881

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4 0
2 years ago
The accepted value for the mass of a moonrock is 46.37 g. In an experiment the rock is measured to be 47.25 g. What is the perce
Artist 52 [7]

Answer:

The answer is

<h2>2.00 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual measurement = 46.37 g

error = 47.25 - 46.37 = 0.88

The percentage error of the measurement is

P(\%) =  \frac{0.88}{46.37}  \times 100 \\  = 1.89777873...

We have the final answer as

<h3>2.00 %</h3>

Hope this helps you

4 0
3 years ago
An elastic cord can be stretched to its elastic limit by a load of 2N.If a 35cm length of the cord is extended 0.6cm by a force
Levart [38]

Explanation:

from \: hookes \: law \\ F = k.e \\ but \: e = 0.6 \: cm \\ 2 = k \times 0.6 \\ k = 3.33 \\ when \:F \: is \: 2.5 \\ 2.5 = 3.33 \times e {}^{.}   \\  {e}^{. }  = 0.75 \: cm \\ new \: length = 35 -  {e}^{.}  \\  = 35 - 0.75 \\  = 34.25 \: cm

3 0
3 years ago
23g of sodium reacted with 35.5g og chlorine calculate the mass of the sodium chloride formed. Help!
Simora [160]
Hope this helps you.

4 0
3 years ago
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