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Elis [28]
3 years ago
10

The Kelvin temperature of sample of 650 cm sample of ammonia gas is doubled what is the new volume of the gas

Chemistry
1 answer:
storchak [24]3 years ago
4 0

Answer:

1300cm3.

Explanation:

Step 1:

Data obtained from the question.

Initial temperature (T1) = K

Initial volume (V1) = 650 cm3

Final temperature (T2) = double the original = 2K

Final volume (V2) =..?

Step 2:

Determination of the new volume of the gas.

The new volume of the gas can be obtained by using Charles' law as follow:

V1/T1 = V2/T2

650/K = V2/2K

Cross multiply

K x V2 = 650 x 2K

Divide both side by K

V2 = 650 x 2K /K

V2 = 650 x 2

V2 = 1300cm3.

Therefore, the new volume of the gas is 1300cm3

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The combustion of 135 mg of a hydrocarbon produces 440 mg of CO2 and 135 mg H2O. The molar mass of the hydrocarbon is 270 g/mol.
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Also from the question, moles of H2O = 0.135/18= 0.0075mole

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