Answer:
Explanation:
mole of O₂ = 
= .25 moles
mole of CO₂
= 
= .1818 moles
moles of SO₂
= .125 moles
Total moles of gas
= .5568 moles.
total volume of gas mixture
= 22.4 x .5568 liter ( volume of one mole of any gas = 22.4 liter)
= 12.47 liter.
gas will exert partial pressure according to their mole fraction
gas having greatest no of moles in the total mole will have greatest mole fraction so
O₂ will have greatest partial pressure.
I would say a. lithium but i am not sure.
I think it will be letter A tbh
Hope this helps you out
Q=mcdeltaT. use this formula and find the answer.
The answer for the following question is explained below.
The option for the following answer is "d".
Explanation:
The phlogiston theory of combustion:(Greek word phlogiston means <u><em>"BURN"</em></u>)
Phlogiston theory states that phlogisticated substances are the substances that contain phlogiston and dephlogisticate when burned.
Dephlogisticating is the process of releasing stored phlogiston,which is absorbed by the air.
Growing plants then absorb this phlogiston,which is why air does not spontaneously combust and also plant matte burns as well as it does.
The prevailing theory was that flammable materials contained a substance called phlogiston that was released during the combustion.
For example:
- phlogiston was transferring into the surrounding air.
