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ZanzabumX [31]
2 years ago
15

How would a sandblasted rock differ from a rock that hasn't been sandblasted?

Chemistry
1 answer:
steposvetlana [31]2 years ago
3 0
A non-sandblasted rock could be rough or smooth depending on how it was formed.

A sandblasted rock should be much smoother, since the sand blasts away any rough edges. It will, however, be slightly smaller due to losing those edges.
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1) Which of the following is a property of matter that can be observed without changing thecomposition of the matter?
vovikov84 [41]

Answer:

Rusting of iron is one form of oxidation. Whether a substance oxidizes or corrodes describes a chemical property of matter.

HOPE THIS HELPS! ^_^

Explanation:

3 0
3 years ago
Read 2 more answers
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timama [110]
Eye protection, fire proof clothing, proper foot gear, just anything that you could prevent yourself from being burned because you are working with flammable materials.
8 0
2 years ago
What are 2 mixtures and explain your answer
liq [111]
Water and orange juice
Or orange juice and sodium chloride
3 0
2 years ago
Of metals and nonmetals which tend to be positive ions​
MA_775_DIABLO [31]

Answer:

metal atoms lose electrons to form positive ions (cations)

Explanation:

metal atoms lose electrons to form positive ions (cations ) non-metal atoms gain electrons to form negative ions (anions )

5 0
3 years ago
Ammonium nitrate is an ingredient in cold packs used by sports trainers for injured athletes. Calculate the change in temperatur
Ronch [10]

Answer:

See explanation

Explanation:

First, we need to use the correct expression:

Q = m*Cp*ΔT  (1)

Q = n*ΔH  (2)

These are the 2 expressions to calculate heat or energy.

Now, we want to know the change of temperature of the nitrate in water after being added, so with the innitial data of nitrate, we can calculate heat using the second expression. First, we need to calculate moles with the molecular mass:

n = m/MM

n = 42/80.1 = 0.52 moles

With these moles, we can calculate heat with the ΔH of this reaction:

Q = 0.52 * 25.7 = 13.364 kJ or 13,364 J

However, this heat as is being absorbed, the value would be negative.

Now that we have heat, we can use expression (1) and plug these values to solve for ΔT, but before, we need to know the total mass of the solution (water + nitrate)

m = 250 + 42 = 292 g

now, solving for ΔT:

-13,364 = 292 * 4.18 * ΔT

ΔT = -13,363 / (292 * 4.18)

ΔT = -10.95 °C

3 0
3 years ago
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