Mole is mass (g) / Molar mass (mole/gram)
So to find mass in gram multiply the no.mole by Molar mass
<h3>
Answer:</h3>
1.2 × 10⁻⁸ mol Pb
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 7.2 × 10¹⁵ atoms Pb
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:
![\displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})](https://tex.z-dn.net/?f=%5Cdisplaystyle%207.2%20%5Ccdot%2010%5E%7B15%7D%20%5C%20atoms%20%5C%20Pb%28%5Cfrac%7B1%20%5C%20mol%20%5C%20Pb%7D%7B6.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20Pb%7D%29)
- [DA] Multiply/Divide [Cancel out units]:
![\displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb](https://tex.z-dn.net/?f=%5Cdisplaystyle%201.19562%20%5Ccdot%2010%5E%7B-8%7D%20%5C%20mol%20%5C%20Pb)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb
Very simply, you get twice as much Hydrogen as Oxygen, because the chemical formula is H2O, meaning two hydrogen atoms bonded to one oxygen atom.
Its A because I did it on connexus