Answer:
Let f be force of friction on the blocks kept on inclined plane. T be tension in the string
For motion of block on the inclined plane in upward direction
T - m₁gsin40 - f = m₁a
f = μ m₁gcos40
For motion of hanging block on in downward direction
m₂g - T = m₂ a
Adding to cancel T
m₂g - - m₁gsin40 - μ m₁gcos40 = a ( m₁+m₂ )
a = g (m₂ - - m₁sin40 - μ m₁cos40) / ( m₁+m₂ )
Putting the values
a = 9.8 ( 4.75 - 2.12-1.045) / 7.6
2.04 m s⁻²
M₂ will go down and M₁ will go up with acceleration .
Explanation:
Answer:
only thing I think of when I see that is 'Just Wondering'
Explanation:
Answer:
Je ne Sachez que Qu’est-ce que le
Answer:
a diagonal line on the graph
Explanation:
the slope would be constant at an increasing rate
y=x
uniform= increasing at a constant rate
