Answer:
The point on the rim
Explanation:
All the points on the disk travels at the same angular speed 
, since they cover the same angular displacement in the same time. Instead, the tangential speed of a point on the disk is given by
where
is the angular speed
r is the distance of the point from the centre of the disk
As we can see, the tangential speed is directly proportional to the distance from the centre: so the point on the rim, having a larger r than the point halway between the rim and the axis, will have a larger tangential speed, and therefore will travel a greater distance in a given time.
Answer:
-929.5Joules
Explanation:
To get the work done by sam, we will calculate the kinetic energy of sam expressed as;
KE = 1/2mv²
m is the mass = 1100kg
v is the velocity = 1.3m/s
KE = 1/2(1100)(1.3)²
KE = 550(1.69)
KE = 929.5Joules
Since Sam is opposing the direction of movement, work done by him will be a negative work i.e -929.5Joules
The ammeter reading (current) will decrease.
V=IR
I = V/R
so I is inversely proportional to R, i.e. increasing R will cause I to decrease
I'm thinking the answer would be D.
I hope this helps ☺ Let me know if you have any others
