Ridge push
convection
slab pull
Answer:
Les plantes produisent de l'oxygène et ont contribué à faire de la Terre une planète habitable. Grâce au processus de photosynthèse pendant la journée, les plantes absorbent le dioxyde de carbone de l'air, le convertissent en sucre et libèrent de l'oxygène dans l'atmosphère.
Les plantes consomment du dioxyde de carbone - un gaz à effet de serre important - au cours du processus de photosynthèse. La réduction du dioxyde de carbone dans l'atmosphère a un effet de refroidissement indirect. Les plantes refroidissent également l'atmosphère car elles libèrent de la vapeur d'eau lorsqu'elles deviennent chaudes, un processus similaire à la transpiration.
la température, l'humidité et l'intensité lumineuse autour de la plante; la concentration de dioxyde de carbone dans l'air autour des feuilles. La relation est inverse; autrement dit, à mesure que la concentration de CO2 augmente, le nombre de stomates produits diminue, et vice versa.
Explanation:
Answer:
(a) 98 N
(b) 158 N
(c) 38 N
Explanation:
<h2>
Part (a)</h2>
When the acceleration is 0 m/s², the net force on the mass is 0 N. Therefore, the tension force is equal to the weight force due to Newton's Second Law:
- ∑F_y = T - w = ma_y
- ∑F_y = T - w = m(0 m/s²)
- ∑F_y = T - w = 0
- ∑F_y = T = w
Since the tension in the cable and the weight of the mass are equal to each other, we can solve for the weight force of the mass by using:
- w = mg
- w = (10 kg)(9.8 m/s²)
- w = 98 N
Since T = w, we can say that T = 98 N.
<h2>Part (b)</h2>
Let's set the upwards direction to be positive and the downwards direction to be negative. We can use Newton's Second Law to solve for the tension in the cable if the acceleration is 6 m/s² upward:
- ∑F_y = T - w = ma_y
- ∑F_y = T - mg = m(6 m/s²)
- ∑F_y = T - mg = 6m
Plug the known values into the equation and solve for T.
- T - mg = 6m
- T - (10 kg)(9.8 m/s²) = 6(10 kg)
- T - 98 = 60
- T = 158 N
The tension in the cable if the acceleration is +6 m/s² is 158 N.
<h2>
Part (c)</h2>
The process is the same, but this time acceleration is -6 m/s².
- ∑F_y = T - w = ma_y
- ∑F_y = T - mg = m(-6 m/s²)
- ∑F_y = T - mg = -6m
Plug known values into the equation and solve for T.
- T - mg = -6m
- T - (10 kg)(9.8 m/s²) = -6(10 kg)
- T - 98 = -60
- T = 38 N
The tension in the cable if the acceleration is -6 m/s² is 38 N.