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musickatia [10]

3 years ago

14

What three mechanisms may drive tectonic plate movement?

1 answer:

Reil [10]3 years ago

8 0

Ridge push
convection
slab pull

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How did einstines and Newton’s theory’s differ in terms of explaining the cause of gravity

qwelly [4]

Answer: in the Newton concluded that objects fall because they are pulled by Earth's gravity. Einstein's interpretation was that these objects do not fall.

Explanation: These objects and Earth just freely move in a curved spacetime and this curvature is induced by mass and energy of these objects. - I HOPE THAT HELPED!!

5 0

3 years ago

Need help!!! A charge of 8.5 × 10–6 C is in an electric field that has a strength of 3.2 × 105 N/C. What is the electric force a

ddd [48]

B is the right answer. Multiply numbers you get the answer

3 0

3 years ago

Read 2 more answers

Four objects are situated along the y axis as follows: a 2.02 kg object is at 3.03 m, a 2.92 kg object is at 2.43 m, a 2.53 kg o

levacccp [35]

Answer:

0.975 m

Explanation:

The center of mass y = ∑m₁y₁/∑m₁ where m₁ = the individual masses and y₁ = the y - coordinates of the individual masses

So,

y = (2.02 kg × 3.03 m + 2.92 kg × 2.43 m + 2.53 kg × 0 m + 4.02 kg × -0.501 m)/(2.02 kg + 2.92 kg + 2.53 kg + 4.02 kg)

y = (6.1206 kgm + 7.0956 kgm + 0 kgm - 2.01402 kgm)/11.49 kg

y = 11.20218 kgm/11.49 kg

y = 0.975 m

So, the y- component of the center of mass of these objects is 0.975 m

8 0

3 years ago

Two kilograms of air is contained in a rigid wellinsulated tank with a volume of 0.6 m3 . The tank is fitted with a paddle wheel

wolverine [178]

Answer:

$0.3\ \text{m}^3/\text{kg}$

$36\ \text{kJ}$

$18\ \text{kJ/kg}$

Explanation:

V = Volume of air = $0.6\ \text{m}^3$

P = Power = 10 W

t = Time = 1 hour

m = Mass of air = 2 kg

Specific volume is given by

$v=\dfrac{V}{m}\\\Rightarrow v=\dfrac{0.6}{2}\\\Rightarrow v=0.3\ \text{m}^3/\text{kg}$

The specific volume at the final state is $0.3\ \text{m}^3/\text{kg}$

Work done is given by

$W=Pt\\\Rightarrow W=10\times 60\times 60\\\Rightarrow W=36000\ \text{J}=36\ \text{kJ}$

The energy transfer by work, is $36\ \text{kJ}$

Change in specific internal energy is given by

$\Delta u=\dfrac{Q}{m}+\dfrac{W}{m}\\\Rightarrow \Delta u=0+\dfrac{36}{2}\\\Rightarrow \Delta u=18\ \text{kJ/kg}$

The change in specific internal energy of the air is $18\ \text{kJ/kg}$

8 0

3 years ago

A garden hose with an internal diameter of 2.9 cm is connected to a (stationary) lawn sprinkler that consists merely of a contai

Alecsey [184]

Answer:

Water leaves the holes with a speed of 2.65 m/sec

Explanation:

It is given internal diameter of garden hose = 2.9 cm

So internal radius $r_1=\frac{2.9}{2}=1.45cm$

Number of holes n = 24

Diameter of holes d = 0.36 cm

So radius of holes $r_2=\frac{0.36}{2}=0.18cm$

Velocity of water in hose $v_1=0.98m/sec$

According to continuity equation

$A_1v_1=nA_2v_2$

$\pi r_1^2\times 0.98=24\times \pi r_2^2\times \times v_2$

$1.45^2\times 0.98=24\times 0.18^2\times \times v_2$

$v_2=2.65m/sec$

Therefore water leaves the holes with a speed of 2.65 m/sec

3 0

4 years ago