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vitfil [10]
4 years ago
14

In a certain oscillating LC circuit, the total energy is converted from electrical energy in the capacitor to magnetic energy in

the inductor in 1.40 μs. What are (a) the period of oscillation in microseconds and (b) the frequency of oscillation? (c) How long after the magnetic energy is a maximum will it be a maximum again?
Physics
1 answer:
aleksandrvk [35]4 years ago
5 0

Answer:

A = 5.6μs

B = 178.57kHz

C = 2.8μs

Explanation:

A. It takes ¼ of the period of the circuit before the total energy is converted from electrical energy in the capacitor to magnetic energy in the inductor.

t = T/4

T = 4*t

T = 4 * 1.4 = 5.6μs

B. f = 1/T

Frequency is the inverse of period

f = 1 / 5.6*10⁻⁶

f = 178571.4286Hz

f = 178.57kHz

C. time taken for maximum energy to occur is T/2

t = 5.6 / 2 = 2.8μs

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therefore, acceleration=90/10

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6. A 1,780kg car moving at 14m/s takes a turn around a circle with a radius of 50.0m.
m_a_m_a [10]

1) Centripetal acceleration: 3.9 m/s^2

2) Centripetal force: 6942 N

Explanation:

1)

For an object moving in uniform circular motion (=circular motion with constant  speed), the net acceleration is the centripetal acceleration, directed towards the centre of the trajectory and whose magnitude is given by

a=\frac{v^2}{r}

where

v is the speed

r is the radius of the circle

For the car in this problem, we have

v = 14 m/s is the speed

r = 50.0 m is the radius

Substituting, we find the acceleration:

a=\frac{14^2}{50.0}=3.9 m/s^2

2)

The net force acting upon the car is the centripetal force, also acting towards the centre of the circular path, and whose magnitude is given by

F=ma

where

m is the mass

a is the centripetal acceleration

For the car in this problem, we have:

m = 1780 kg is the mass

a=3.9 m/s^2 is the acceleration

Substituting, we find the centripetal force:

F=(1780)(3.9)=6942 N

Learn more about centripetal acceleration and force:

brainly.com/question/2562955

#LearnwithBrainly

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