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2 answers:
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Answer:
In a quadratic equation of the shape:
y = a*x^2 + b*x + c
we hate that the discriminant is equal to:
D = b^2 - 4*a*c
This thing appears in the Bhaskara's formula for the roots of the quadratic equation:
You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)
If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)
If D > 0 we have two different roots, so the graph touches the x-axis in two different points.
Answer:
x=7 (if your teacher cares it could + or - 7)
Step-by-step explanation:
Okay, since it's a 90 degree triangle you can use the Pythagorean theorem
( a^2 + b^2 = c^2)
Since it's an isosceles triangle the other side is x because it's the same value.
x^2 + x^2= (7 )^2
Add the left side
2x^2= 7^2 + ^2 roots and square roots cancel each other out
So -> 2x^2= 49 x 2 =98
just solve for x.
x^2 = 98/2
x^2= 49
Square root both sides
x= 7