If it is isosceles angle E must be equal to F, in this case 75°
Answer:
<em>7,078,912 cents</em>
Step-by-step explanation:
Given the formula for calculating the value of the account in t years as;
V = Pe^rt
P is the principal initially invested
e is the base of a natural logarithm,
r is the rate of interest
t is the time
Given
P = $51200
r = 5.4% = 0.054
t = 6years
Substitute
V = 51200e^(0.054)(6)
V = 51200e^(0.324)
V = 51200(1.3826)
V = $70,789.12
V = 7,078,912 cents
<em>hence the amount in the account after 6 years to the nearest cent is 7,078,912 cents</em>
I googled it because I wasn’t sure if there’s decimals needed but with the raw number I got -0.69333333333
Hope it helped.
Answer: 1. C(12) 2. B(n-1-14) 3. A(30)
Step-by-step explanation: For number one the nth term with common difference d and first term a is a+(n-1)d=nth term, plug in the values you have and solve for n to get 12. For number 2 an algebraic expression has a variable and a constant but doesn't have an equal sign. So it is B. For number three just add them up. Hope this helped!
At time t = 0 the pool is empty. At time t = 6 hours the pool is full. Once you have a function that represents the amount of water in the pool, you should be able to put any value for t in the domain 0 <= t <= 6 to find the amount of water in the pool. t can be any real number such as: 1, 1.5, 2.8, 3.6589, etc. So all real numbers from 0 to 6 hours.
