Not necessarily.
and
may be linearly dependent, so that their span forms a subspace of
that does not contain every vector in
.
For example, we could have
and
. Any vector
of the form
, where
, is impossible to obtain as a linear combination of these
and
, since
unless
and
.
Answer:
Step-by-step explanation:
The given function is
Let
Interchange x and y.
Solve for y,
Divide both sides by 2
Therefore;
Well, 10 can go into 56, 5 times, so your whole number would be 5.
Then 50 (where did i get 50 from? 5 times the ten is 50) minues 56 is 6. So it would be :
5 and 6/10 (your denominator stays the same)
But it needs o be simplafied to its lowest terms. They are both divisable by 2, SOO 6 divided by 2 is 3, and 10 divided by 2 is 5 So, your new fraction is:
5 and 3/5 in which it cant be simplafied anymore.
<em>~ 5 3/5 </em><em>is your answer :)</em>
Answer:
She need to walk 31/75 miles to school.
Step-by-step explanation:
It is given that,
Sofia has walk 
miles to school. She has already walk 
of a mile.
We need to find how much farther does she need to walk.
Total distance = 
Let she has to walk x distance to school.
Hence, she need to walk 31/75 miles to school.
The answer should be t=-24
