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Nuetrik [128]
3 years ago
7

A long copper bar of rectangular cross-section, whose width w is much greater than its thickness L, is maintained in contact wit

h a heat sink at its lower surface, and the temperature throughout the bar is approximately equal to that of the sink, To. Suddenly, an electric current is passed through the bar and an airstream of temperature T is passed over the top surface, while the bottom surface continues to be maintained at To. Obtain the differential equation and the top surface boundary condition that could be solved to determine the temperature as a function of position and time in the bar.
Physics
1 answer:
Tamiku [17]3 years ago
6 0
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Suppose a soup can is made from a sheet of steel19 which is .13 mm thick. If the can is 11 cm high and 6 cm in diameter, use dif
Flura [38]

Answer:

The can mass is 0,00359 kg or 3,59 g

Explanation:

1. Relevant Data:

Steel thickness= 0.13 mm or 0.013 mm

h=11 cm

d=6 cm

ρ=800 kg/m^3

2. Calculate mass from densisty equation:

\rho=\frac{m}{v}, then m=\rho .v

We need to estimate the volume of the can to calculate the mass.

3. Estimate volume using differentials:

Cylinder volume equation is:

V=\frac{1}{4}\pi  d^{2}h

Considering that the can is an object with a hole inside, then we need to estimate the real volume of the sheet of steel.

Using differentials we have:

dV=\frac{1}{2}\pi  Dh (dD)

Then, we could say that dD=0.013 cm

Replacing the values of d, h and dD, we obtain:

dV=\frac{1}{6}\pi  (6 cm)(11 cm)(0,013 cm)

dV=0,4492 cm^3

4. Calculate the mass

Convert volume unit into m^3

0,4492 cm^3x\frac{1 m^3}{1x10^6 cm^3} =0,4492 x 10^-6 m^3

Calculate mass

m=\rho .v

m=8000 \frac{kg}{m^3}.0,4492 x10^-6 m^3

m=0,00359 kg =3,59 g

5 0
4 years ago
You toss a ball into the air and note the time interval between the ball leaving your hand and reaching its highest position. Wh
lawyer [7]

Answer:

It is longer

Explanation:

According to the theory of special relativity, moving clocks run slower. So, the construction worker moving at a constant speed observers a time much longer than the time I observe since I am stationary. If t is the time observed by me and v is the speed of the construction worker, then, the time observed by the construction worker, t' is given by

t' = t/√[1 - (v/c)²] where c = speed of light

So, the construction worker reports a longer time interval than me since his time runs slower.

8 0
3 years ago
According to the picture, what is the truck doing?
Slav-nsk [51]

Answer:

but were is the picture

how can we see

4 0
3 years ago
In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the max
Sav [38]

Answer:

the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94

Explanation:

Given that ;

the top speed of Cheetahs is almost 60 mph

In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2

The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

From the knowledge of Newton's Law;

we knew that ;

Force F = mass m × acceleration a

Also;

The net force  F_{net}  = frictional force \mu_k mg

so we can say that;

m×a = \mu_k mg

where;

the coefficient of static friction \mu_k is:

\mu_k = \dfrac{m*a}{m*g}

\mu_k = \dfrac{a}{g}

\mu_k = \dfrac{19 \ m/s^2}{9.81 \ m/s^2}

\mathbf{\mu_k} = 1.94

Hence; the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94

5 0
3 years ago
The raising and lifting the ball by kicking is called
Minchanka [31]

The raising and lifting the ball by kicking is a B) Scoop

6 0
3 years ago
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