Answer:
My mom always told me he was just there
Explanation:
Answer:
The velocity of mass 2m is ![v_B = 0.67 m/s](https://tex.z-dn.net/?f=v_B%20%3D%200.67%20m%2Fs)
Explanation:
From the question w are told that
The mass of the billiard ball A is =m
The initial speed of the billiard ball A =
=1 m/s
The mass of the billiard ball B is = 2 m
The initial speed of the billiard ball B = 0
Let the final speed of the billiard ball A = ![v_A](https://tex.z-dn.net/?f=v_A)
Let The finial speed of the billiard ball B = ![v_B](https://tex.z-dn.net/?f=v_B)
According to the law of conservation of Energy
![\frac{1}{2} m (v_1)^2 + \frac{1}{2} 2m (0) ^ 2 = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20m%20%28v_1%29%5E2%20%2B%20%5Cfrac%7B1%7D%7B2%7D%202m%20%280%29%20%5E%202%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20m%20%28v_A%29%5E2%20%2B%20%5Cfrac%7B1%7D%7B2%7D%202m%20%28v_B%29%5E2)
Substituting values
![\frac{1}{2} m (1)^2 = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20m%20%281%29%5E2%20%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20m%20%28v_A%29%5E2%20%2B%20%5Cfrac%7B1%7D%7B2%7D%202m%20%28v_B%29%5E2)
Multiplying through by ![\frac{1}{2}m](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dm)
![1 =v_A^2 + 2 v_B ^2 ---(1)](https://tex.z-dn.net/?f=1%20%3Dv_A%5E2%20%2B%202%20v_B%20%5E2%20---%281%29)
According to the law of conservation of Momentum
![mv_1 + 2m(0) = mv_A + 2m v_B](https://tex.z-dn.net/?f=mv_1%20%2B%202m%280%29%20%3D%20mv_A%20%2B%202m%20v_B)
Substituting values
![m(1) = mv_A + 2mv_B](https://tex.z-dn.net/?f=m%281%29%20%20%3D%20mv_A%20%2B%202mv_B)
Multiplying through by ![m](https://tex.z-dn.net/?f=m)
![1 = v_A + 2v_B ---(2)](https://tex.z-dn.net/?f=1%20%3D%20v_A%20%2B%202v_B%20---%282%29)
making
subject of the equation 2
![v_A = 1 - 2v_B](https://tex.z-dn.net/?f=v_A%20%3D%201%20-%202v_B)
Substituting this into equation 1
![(1 -2v_B)^2 + 2v_B^2 = 1](https://tex.z-dn.net/?f=%281%20-2v_B%29%5E2%20%2B%202v_B%5E2%20%3D%201)
![1 - 4v_B + 4v_B^2 + 2v_B^2 =1](https://tex.z-dn.net/?f=1%20-%204v_B%20%2B%204v_B%5E2%20%2B%202v_B%5E2%20%3D1)
![6v_B^2 -4v_B +1 =1](https://tex.z-dn.net/?f=6v_B%5E2%20%20-4v_B%20%2B1%20%3D1)
![6v_B^2 -4v_B =0](https://tex.z-dn.net/?f=6v_B%5E2%20-4v_B%20%3D0)
Multiplying through by ![\frac{1}{v_B}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bv_B%7D)
![6v_B -4 = 0](https://tex.z-dn.net/?f=6v_B%20-4%20%3D%200)
![v_B = \frac{4}{6}](https://tex.z-dn.net/?f=v_B%20%3D%20%5Cfrac%7B4%7D%7B6%7D)
![v_B = 0.67 m/s](https://tex.z-dn.net/?f=v_B%20%3D%200.67%20m%2Fs)
Answer: through digested food
Explanation: cells get their sugar molecules from the food that is taken in by an organism. The food taken in is digested by the stomach into base materials like sugar, fatty acids and amino acids. These base materials are circulated through the blood till they get to the cells where they are needed.
Answer:
the pressure per square inch is greater from the smaller feet.
Explanation:
different weight distribution
<span>22.5 newtons.
First, let's determine how much energy the stone had at the moment of impact. Kinetic energy is expressed as:
E = 0.5mv^2
where
E = Energy
m = mass
v = velocity
Substituting known values and solving gives:
E = 0.5 3.06 kg (7 m/s)^2
E = 1.53 kg 49 m^2/s^2
E = 74.97 kg*m^2/s^2
Now ignoring air resistance, how much energy should the rock have had?
We have a 3.06 kg moving over a distance of 10.0 m under a force of 9.8 m/s^2. So
3.06 kg * 10.0 m * 9.8 m/s^2 = 299.88 kg*m^2/s^2
So without air friction, we would have had 299.88 Joules of energy, but due to air friction we only have 74.97 Joules. The loss of energy is
299.88 J - 74.97 J = 224.91 J
So we can claim that 224.91 Joules of work was performed over a distance of 10 meters. So let's do the division.
224.91 J / 10 m
= 224.91 kg*m^2/s^2 / 10 m
= 22.491 kg*m/s^2
= 22.491 N
Rounding to 3 significant figures gives an average force of 22.5 newtons.</span>