Answer:
(a) 91 kg (2 s.f.) (b) 22 m
Explanation:
Since it is stated that a constant horizontal force is applied to the block of ice, we know that the block of ice travels with a constant acceleration and but not with a constant velocity.
(a)

Subsequently,

*Note that the equations used above assume constant acceleration is being applied to the system. However, in the case of non-uniform motion, these equations will no longer be valid and in turn, calculus will be used to analyze such motions.
(b) To find the final velocity of the ice block at the end of the first 5 seconds,

According to Newton's First Law which states objects will remain at rest
or in uniform motion (moving at constant velocity) unless acted upon by
an external force. Hence, the block of ice by the end of the first 5
seconds, experiences no acceleration (a = 0) but travels with a constant
velocity of 4.4
.

Therefore, the ice block traveled 22 m in the next 5 seconds after the
worker stops pushing it.
Answer:
a) 23.51 m/s
b) 1.07 kg
Explanation:
Parameters given:
Kinetic energy, K = 295 J
Momentum, p = 25.1 kgm/s
a) The kinetic energy of a body is given as:

where m = mass of the body and v = speed of the body
We know that momentum is given as:
p = mv
Therefore:
K = 1/2 * pv
=> v = 2K / p
v = (2 * 295) / 25.1 = 23.51 m/s
The velocity of the body at that instant is 23.51 m/s.
b) Momentum is given as:
p = mv
=> m = p / v
m = 25.1 / 23.51 = 1.07 kg
The mass of the body at that instant is 1.07 kg
Sorry Man If you ask this question no one wants to write an essay and waste their time. You are smart enough to write an essay.
Answer:
A) B = 0.009185 T
B) Drection is negative y-direction
Explanation:
A) We are given;
Speed(v) = 2.5 x 10^(7) m/s
Acceleration (a) = 2.2 x 10^(13) m/s²
We also know that charge of proton(q) = 1.6 x 10^(-19)
Mass of proton(m) = 1.67 x 10^(-27)
Now, Since the proton is moving by circular motion, this force is equal to the centripetal force which is given as;
F = qvBsinθ = ma
Since perpendicular, θ = 90°
And so, sinθ = sin 90 = 1
Thus, qvB = ma
Making B the subject gives;
B = ma/qv
B = (1.67 X 10^(-27) X 2.2 X 10^13)) / (1.6 X 10^(-19) X 2.5 X 10^(7))
= 0.009185 T
B) By use of Flemings right hand rule, we can see that the middle finger points toward negative y-direction, so the magnetic field is in the negative y-direction
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