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r-ruslan [8.4K]
3 years ago
13

According to the picture, what is the truck doing?

Physics
1 answer:
Slav-nsk [51]3 years ago
4 0

Answer:

but were is the picture

how can we see

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An object is placed in front of a thin converging lens of focal length 12 cm. The image of the object is upright and 2.5 times a
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Digamos que unos 4.2 centímetros
8 0
3 years ago
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The reactants for a certain chemical reaction are shown. Cu(NO3)2 + NaOH → Which of the following shows the correct product or p
valentinak56 [21]

Answer : The products of this reaction are, Cu(OH)_2 and NaNO_3

Explanation :

First we have to write the balanced chemical reaction.

Cu(NO_3)_2+2NaOH\rightarrow Cu(OH)_2+2NaNO_3

In this reaction, 1 mole of copper nitrate react with the 2 moles of sodium hydroxide to give 1 mole of copper hydroxide and 2 moles of sodium nitrate.

This reaction is a double displacement reaction.

Double displacement reaction : A type of reaction in which a positive cation and a negative anion of two reactants react to exchange their places to form two new products.

The general representation of this reaction is,

XY+AB\rightarrow XB+AY

(X and A are the cations, Y and B are the anions)

Hence, the products of this reaction are, copper hydroxide,Cu(OH)_2 and sodium nitrate,NaNO_3

6 0
3 years ago
. Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 1.00 × 104 kg. The thrust of its engin
Viktor [21]

Answer:

a) The module's acceleration in a vertical takeoff from the Moon will be 1.377 \frac{m}{s^2}

b) Then we can say that a thrust of 3*10^{4} N won't be able to lift off the module from the Earth because it's smaller than the module's weight (9.8 *10^{4} N).

Explanation:

a) During a vertical takeoff, the sum of the forces in the vertical axis will be equal to mass times the module's acceleration. In this this case, the thrust of the module's engines and the total module's weight are the only vertical forces. (In the Moon, the module's weight will be equal to its mass times the Moon's gravity acceleration)

T-(m*g)=m*a

Where:

T= thrust =3 *10^{4} N

m= module's mass =1 *10^{4} N

g= moon's gravity acceleration =1.623 \frac{m}{s^2}

a= module's acceleration during takeoff

Then, we can find the acceleration like this:

a=\frac{T}{m} -g=\frac{3*{10}^4 N}{1*{10}^4 kg}-1.623\frac{m}{s^2}

a=1.377 \frac{m}{s^2}

The module's acceleration in a vertical takeoff from the Moon will be 1.377 \frac{m}{s^2}

b) To takeoff, the module's engines must generate a thrust bigger than the module's weight, which will be its mass times the Earth's gravity acceleration.

weight=m*g=(1*{10}^4 kg)*(9.8 \frac{m}{s^2})=9.8 *10^{4} N

Then we can say that a thrust of 3*10^{4} N won't be able to lift off the module from the Earth because it's smaller than the module's weight (9.8 *10^{4} N).

8 0
4 years ago
Archimedes supposedly was asked to determine whether a crown made for the king consisted of puregold. According to legend, he so
DENIUS [597]

Answer:

the crown was not made of pure gold

Explanation:

Mass of gold = weight in air/ g = 7.84N/10ms-2= 0.784 Kg or 0.8Kg

From Archimedes principle:

Upthrust= weight in air- weight in a fluid

Upthrust= volume × density × g

Note density of water = 1000kgm-3

7.84-6.84= V × 1000kgm-3×10ms-2

V= 1/10000= 1×10-4 m^3

Density = mass/ volume= 0.8/1×10-4

= 8×10^3 Kgm-3

But we know the density of gold to be 19.3 ×10^3 kgm-3

Hence the crown was not made of pure gold

4 0
3 years ago
If you go outside on a hot summer day with a double scoop ice cream cone, how will the cold ice cream interact with the hot outs
lesya [120]
Well a simple answer would be it would start to melt because icecream is a liquid unless its frozen,just like ice.
3 0
3 years ago
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