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V125BC [204]
2 years ago
15

To make lemonade Erica dissolved 30 g of sugar in a certain amount of water. By what amount is the mass of water likely to incre

ase after the sugar dissolves?
A. 0 g
B. 10 g
C. 15 g
D. 30 g
Chemistry
1 answer:
Brrunno [24]2 years ago
4 0

Answer:

D. 30 g

Explanation:

Conversion of mass ensures that though the sugar may appear gone the particles remain and will only add onto the original liquid

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Please help!-- 20 pts!
ratelena [41]

Answer:

Both oil and gasoline molecules are nonpolar, while water is polar. Nonpolar solvents have a tendency to dissolve other nonpolar molecules.

Explanation:

Molecules may be categorized as "polar" or "nonpolar" according to <em>difference in the atom's electronegativity.</em>

<u>Water is polar</u> because it consists of two types of atoms that<em> do not cancel out each other.</em> It is made of two atoms of Hydrogen and only one atom of Oxygen. This makes the Oxygen<u> partially negative</u> and the Hydrogen <u>partially positive.</u> This allows them to readily bond with other polar molecules like sugar. However, it cannot mix freely with oil and gasoline because<em> both of these are nonpolar. </em>Nonpolar molecules do not have much difference when it comes to their atoms' electronegativity. <em>Therefore, they have the tendency to dissolve molecules which are nonpolar as well. </em>This explains why oil molecules can mix freely with gasoline.

5 0
2 years ago
1 pts
stealth61 [152]
Its true . air particles move faster when heated and collide with each other
3 0
3 years ago
Help ASAP!!!!!!!!!!!!!!!!!!!!!!!!!
BartSMP [9]

Answer:

ok      .

Explanation:            

3 0
3 years ago
29. What is E for a system which has the following two steps:
jasenka [17]

Answer:

Zero

Explanation:

Recall that;

E = q + w

Where;

q = heat, w = work done

When heat is absorbed by the system q is positive

When heat is evolved by the system q is negative

When the system does work, w is negative

When work is done on the system w is positive

Step 1

ΔE1= 60 KJ + 40 KJ = 100KJ

Step 2

ΔE2= (-30 KJ) + (-70 KJ) = (-100) KJ

ΔE1 + ΔE2= 100KJ + (-100) KJ = 0KJ

4 0
3 years ago
Given that a 12.00 g milk chocolate bar contains 8.000 g of sugar, calculate the percentage of sugar present in 12.00 g of milk
neonofarm [45]
So in order for us to know the percentage of sugar present in a 12.00 g of milk chocolate, what we are going to do is that, we just have to divide 8 by 12 and multiply in by 100 and we get 66.67. Therefore, the percentage of sugar present in 12.00 g of milk chocolate bar is 66.67%. Hope this answers your question. Have a great day!
5 0
3 years ago
Read 2 more answers
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