The moles of potassium that you would need to prepare 1200 g of 5% potassium sulfate solution is 1.538 moles
calculation
calculate the mass potassium using the below formula
%M/M = mass of the solute(potassium)/mass of the solvent (potassium sulfate solution)
let the mass of potassium be represented by Y
then convert % into fraction = 5/100
5/100 = Y/1200
cross multiplication
100y = 6000
divide both side by 100
Y= 60 g
moles of potassium =mass/molar mass
= 60/39=1.538
Answer:
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Explanation:
Answer: 2.0 fianal volume
Explanation:
This in accordance with Boyle's law which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume.
P1V1 = P2V2
Now compare this to Charles ' law which states that the product of the initial volume and the final temperature is equal to the product of the final volume and initial temperature.
V1T2= V2T1
Remember that all temperatures must be calculated in kelvin
If the initial temperature of 273 K is doubled to 546 K,
then a initial volume of 1.0 liter is also doubled, with a final volume of 2.0 liters.