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2 years ago

Write the names of stages in the life cycle of butterfly

Chemistry

1 answer:

stepladder [879]2 years ago

3 0

Answer:

There are four stages in the metamorphosis of butterflies and moths: egg, larva, pupa, and adult.

Hope this helps :)

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The combination of oxygen with other substances to produce new chemical products is called

Flauer [41]

Answer:

The combination of oxygen with other substances to produce new chemical products is called Oxidation.

Explanation:

Oxidation reactions are defined as,

In terms of Inorganic chemistry:

(i) Removal of Electrons:

Example: Mg → Mg²⁺ + 2 e⁻

(ii) Addition of Oxygen:

Example: 2 Mg + O₂ → 2 MgO

In terms of Organic chemistry:

(i) Addition of Electrons:

Example: Cl₂ + 2 e⁻ → 2 Cl⁻

(ii) Addition of Hydrogen:

Example: H₂CCH₂ + H₂ → H₃CCH₃

4 0

3 years ago

Which of the following is not a step in the conversion of 1.3 dam3 to L?

Tanya [424]

First put the choices,and the answer is (10^-3L/1mL)^3 is the correct answer.

3 0

2 years ago

Consider the five balanced chemical reactions listed below, all using O2 as a reactant. Normally, O2 is an excess reagent for re

ad-work [718]

Answer: option E. None because in all the reactions O2 is in excess

Explanation:

7 0

2 years ago

One method for preparing pure iron from Fe2O3 is by reaction with carbon monoxide.Fe2O3(s)+CO(g)→Fe(s)+CO2(g) How many moles of

larisa [96]

Answer:

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

Explanation:

Given data:

Mass of Fe₂O₃ = 122 Kg ( 122×1000 = 122000 g)

Moles of CO = ?

Solution:

Chemical equation:

Fe₂O₃ + 3CO → 2Fe + 3CO₂

Number of moles of Fe₂O₃:

Number of moles = mass/ molar mass

Number of moles = 122000 g /159.69 g/mol

Number of moles = 764 mol

Now we will compare the moles of Fe₂O₃ with CO.

Fe₂O₃ : CO

1 : 3

764 : 3×764 =2292 mol

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

6 0

3 years ago

When solving a problem it is important to identify your given and needed units, but it is also important to understand the relat

Angelina_Jolie [31]

Answer:

The question has some details missing. here are the details ; Given the following ;

1. 43.2 g of tablet with 20 cm3 of space

2. 5 cm3 of tablets weighs 10.8 g

3. 5 g of balsa wood with density 0.16 g/cm3

4. 150 g of iron. With density 79g/cm 3

5. 32 cm3 sample of gold with density 19.3 g/cm3

6. 18 ml of cooking oil with density 0.92 g/ml

Explanation:

Appropriate for calculating mass

32 cm3 sample of gold with density 19.3 g/cm3

18 ml of cooking oil with density 0.92 g/ml

Appropriate for calculating volume

5 g of balsa wood with density 0.16 g/cm3

150 g of iron. With density 79g/cm 3

Appropriate for calculating density

43.2 g of tablet with 20 cm3 of space

5 cm3 of tablets weighs 10.8 g

3 0

2 years ago