Answer:
C. 30.0 g NaOH and add water until the final solution has a volume of 3.00 L.
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
from the question ,
M = 0.250M
V = 3.00 L
M = n / V
n = M * v
n = 0.250M * 3.00 L = 0.75 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
n = 0.75 mol NaOH
m = molecular mass of NaOH = 40 g/mol
n = w / m
w = n * m
w = 0.75 mol * 40 g/mol = 30.0 g
Hence , by using 30.0 g of NaOH and dissolving it to make up the volume to 3 L , a solution of 0.250 M can be prepared .
<u>Answer:</u>
<em>The molarity of the
solution is
</em>
<em></em>
<u>Explanation:</u>
The Balanced chemical equation is

Mole ratio of
: KCl is 1 : 1
So moles
= moles KCl





So Molarity


= 0.000402M or mol/L is the Answer
(Or)
is the Answer
The normal atomic orbitals are joined mathematically during the process of hybridization to create new atomic orbitals known as hybrid orbitals. Even if hybrid orbitals are not identical to regular atomic orbitals.
<h3>What are atomic orbitals?</h3>
Atomic theory & quantum mechanics use the mathematical concept of a "atomic orbital" to describe the location and wavelike behavior of an electron within an atom. Each of those orbitals can contain a maximum of electron pairs, each with a unique spin quantum number s.
<h3>How are atomic orbitals calculated?</h3>
Within every of an atom's shells, various orbital combinations can be found. The n=1 shell has just s orbitals; the n=2 shell contains s and p orbitals; the n=3 shell contains s, p, and d orbitals; and the n=4 up shells include all four types of orbitals.
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Im not sure if this will help but... your subscripts in a balanced equation are used to calculate the molar mass of the compound. And your coefficients are used to get the ratios. so for example we have this balanced equation
Be3N2 + 6H2O= 3Be(OH)2 + 2NH3 and you have to find the molar mass of 6h2o, you need to multiply the subscript by the atomic mass and then add them together to get the overall molar mass. * 2(1.01) + 16.00= 18.02 g/mol
and if a question wants to know the limiting or excess regent you would use the coefficients to find out the ratio between the compounds.