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stiv31 [10]
3 years ago
11

2N2 + 3H2 → 2NH3

Chemistry
1 answer:
andrew-mc [135]3 years ago
3 0

Answer:D

Explanation:

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If the bucket were left outside on a hot day but brought inside before any evaporation occurred, how would the mass be affected?
dangina [55]
It wouldnt because nothing changed
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3 years ago
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n a classroom, which comparison would a teacher most likely use for describing a mole? a cup of water and a liter of oil a dozen
s344n2d4d5 [400]

The teacher would use a dozen eggs and a dozen jellybeans to describe a mole.

A mole is simply a <em>number</em> of things.

Just as a dozen eggs is the <em>same number</em> as a dozen jellybeans, a mole of eggs is the <em>same number</em> as a mole of jellybeans.

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What is the relationship between concentration and rate of reaction?
grigory [225]
<h3><u>Answer;</u></h3>

Directly proportional

<h3><u>Explanation;</u></h3>
  • <em><u>Concentration is one of the factors that determine the rate of a reaction. Reaction rates increases with increase in the concentration of the reactants, which means they are directly proportional.</u></em>
  • An increase in the concentration of reactants produces more collisions and thus increasing the rate at which the reaction is taking place. Therefore, <u>Increasing the concentration of a reactant increases the frequency of collisions between reactants and will cause an increase in the rate of reaction.</u>
7 0
4 years ago
A change in matter that produces new substances is called a _____. 1.mixture 2.physical change 3.solution 4.chemical change
12345 [234]

Answer:

Chemical Change

Explanation:

chemical bonds within the substance have been altered because a new substance has been produced. It cannot be a mixture because they do not involve changes in matter, it cannot be a physical change because they do not result in new substances, it is not a solution because those do not involve changes in matter.

7 0
3 years ago
How would you prepare 1 liter of .030 m copper 2 sulfate pentahydrate?
Ierofanga [76]
Answer is: dissolve 74,9 grams CuSO₄·5H₂O in one liter volumetric flask.
V(CuSO₄·5H₂O) = 1 L.
c(CuSO₄·5H₂O) = 0,30 mol/L.
n(CuSO₄·5H₂O)  = V(CuSO₄·5H₂O) · c(CuSO₄·5H₂O) .
n(CuSO₄·5H₂O) = 1 L · 0,3 mol/L.
n(CuSO₄·5H₂O) = 0,3 mol.
m(CuSO₄·5H₂O) = n(CuSO₄·5H₂O) · M(CuSO₄·5H₂O).
m(CuSO₄·5H₂O) = 0,3 mol · 249,7 g/mol.
m(CuSO₄·5H₂O) = 74,9 g.
5 0
3 years ago
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