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Blizzard [7]
3 years ago
9

How do you calibrate an electronic analytical balance​

Chemistry
1 answer:
Paraphin [41]3 years ago
5 0

Explanation:

For the calibration process, use a weight that is 50% of the scale's capacity for accurate calibration. Weights less than 10% can result in inaccuracy. Make sure that the scale doesn't have any weights placed on it and nothing is rubbing against the scale or the platform.

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Earth carrying capacity is determined by our ?
AleksandrR [38]

Answer:

D. B. C. A.

Yours goals for the future are immediately directed by your quality of life although dictated by your lifespan.

8 0
3 years ago
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At what temperature does a gas at 1.00 atm and 20 degree Celsius have a pressure of 4.00 atm.
vfiekz [6]

Answer:

P1 =4 atm

T1= 20°C

P2=1 atm

T2=?

According to Gay-Lussac's Law or Third Gas Law,

P1T2=P2T1

4×T2=1×20

T2= 20/4

T2= 5°C

Answer At 5°C temperature does a gas at 1.00 atm !

7 0
3 years ago
Harry has a sample of an unknown material. The sample has a mass of 81 grams and a volume of 0.9 cubic centimeters. What is the
Salsk061 [2.6K]
Density = mass/volume
density = 81 grams/0.9 cubic centimetersdensity = 90 grams per cubic centimeter
The density of the sample is 90 grams per cubic centimeter.
8 0
3 years ago
Write the complete thermochemical equation (including energy) for the combustion of hexane.
antoniya [11.8K]
2C₆H₁₄+19O₂⇒14H₂O+12CO₂+energy
You can tell that the energy is on the left side since the reactoin is highly exothermic meaning it releases heat which can also be thought of as energy.

I hope this helps
5 0
3 years ago
A 5.00 gram sample of an oxide of lead PbxOy contains 4.33 g of lead. Determine simplest formula for the compund
Harrizon [31]

Answer: The empirical formula is PbO_2

Explanation:

Mass of Pb =  4.33 g

Mass of O = (5.00-4.33) g = 0.67 g

Step 1 : convert given masses into moles

Moles of Pb =\frac{\text{ given mass of Pb}}{\text{ molar mass of Pb}}= \frac{4.33g}{207g/mole}=0.021moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{0.67g}{16g/mole}=0.042moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Pb = \frac{0.021}{0.021}=1

For O = \frac{0.042}{0.021}=2

The ratio of Pb O=  1: 2

Hence the empirical formula is PbO_2

6 0
3 years ago
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