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never [62]
3 years ago
9

Complete this sentence. If mass remains the same while the volume of a substance ________, the density of the substance will____

___________.
(NOT GIVING BRAINLIEST, JUST ANSWERING A QUESTION MOST PEOPLE GOT WRONG ON)
A. decreases, decrease
B. increases, decrease
C. increases, stay the same
D. decreases, stay the same
**It's D**
Chemistry
1 answer:
VARVARA [1.3K]3 years ago
4 0

Answer:

B. Increases, Decreases

Explanation:

I majored in Chemistry

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The solubility of CaSO4 in pure water at 0oC is 1.09 gram(s) per liter. The value of the solubility product is g
malfutka [58]

Answer: See image attached!

Good luck with your future exams!

7 0
3 years ago
Given a container of helium gas with an initial volume of
Gnoma [55]

Answer:

v2 = 3.9 L

Explanation:

3 0
3 years ago
Balance the equation in the box. Click in the answer box to activate the palette. N2(g) + H2(g) → NH3(g)
lesantik [10]

Answer:

N2(g) + 3H2(g) → 2 NH3(g)

Explanation:

N2(g) + H2(g) → NH3(g)

We start equaling the number of N atoms in both sides multiplying by 2 the NH3.

N2(g) + H2(g) → 2 NH3(g)

So we equals the H atoms (there are six in products sites)

N2(g) + 3 H2(g) → 2 NH3(g)

7 0
3 years ago
What is the final volume of NaOH solution prepared from 100.0 mL of 0.500 M NaOH if you wanted the final concentration to be 0.1
suter [353]

Answer:

The final volume of NaOH solution is 30ml

Explanation:

We all know that

              V1S1 = V2S2

             or V1= V2S2÷S1

             or  V1= V2×S2×1/S1

             or   V1=100×0.15×1/0.50

                    V1= 30

∴30 ml NaOH solution is required to prepare 0.15 M from 100ml 0.50 M NaOH solution.

5 0
3 years ago
The most likely van't Hoff factor for an 0.01 m calcium iodide solution is
monitta

This problem is providing us with the molality of a solution of calcium iodide as 0.01 m. So the most likely van't Hoff factor is required and theoretically found to be 3 due to the following:

<h3>Van't Hoff factor:</h3>

In chemistry, the correct characterization of solutions also imply the identification of the ions it will release in aqueous solution. For that reason, the van't Hoff factor gives us an idea of this number, according to the formula the solute has got.

In such a way, for calcium iodide, we write its ionization equation as shown below:

CaI_2\rightarrow Ca^{2+}+2I^-

Assuming it is able to ionize due to the low molality, because if it was higher, then it won't ionize. Hence, since we have three moles of ion products, one Ca²⁺ and two I⁻, we can conclude the van't Hoff factor would be 3, although calculations may lead to a different, yet close result.

Learn more about the van't Hoff factor: brainly.com/question/23764376

5 0
3 years ago
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