All categories

3 years ago

32P can be used to make any nucleotide (A, C, G, or T) radioactive. Which of the following explains why this is true?

1 answer:

3 0

B. The answer is: All nucleotides have a phosphorus atom that can be replaced with 32P.

Nucleotides contain a nitrogenous base, a five-carbon sugar, and, at least, one phosphate group. Exactly that phosphate group in the nucleotide has the phosphorus atom. Therefore, the phosphorus atom in the nucleotide can be replaced with radioactive phosphorus-32 (32P).

You might be interested in

He following balanced equation shows the formation of water. 2H2 + O2 mc020-1.jpg 2H2O How many moles of oxygen (O2) are require

mrs_skeptik [129]

Answer : The correct option is, 13.7 mole

Solution : Given,

Moles of $H_2$ = 27.4 moles

The given balanced chemical reaction is,

$2H_2+O_2\rightarrow 2H_2O$

From the balanced chemical reaction, we conclude that

As, 2 moles of $H_2$ react with 1 moles of $O_2$

So, 27.4 moles of $H_2$ react with $\frac{27.4}{2}=13.7$ moles of $O_2$

Therefore, the number of moles of oxygen $O_2$ required are, 13.7 moles

7 0

3 years ago

Read 2 more answers

For the reaction 2hno3 + mg(oh)2 → mg(no3)2 + 2h2o, how many moles of magnesium nitrate are produced from 8.00 moles of nitric a

Sladkaya [172]

You would get four moles of magnesium nitrate :) you would have to
“ ?molesmg(oh)2 = 8molmg(no3)2 x molmg(oh)2 / 2molhno3 = 4 moles of magnesium nitrate :))) hopefully this helps! <3

7 0

3 years ago

What, according to you, are the necessary activities that a penetration tester needs to perform while conducting a penetration t

bogdanovich [222]

Answer: First of all planning is done to set the goals to how to test the target. then scanning is done. after that target is uncovered to see how the target exploits by the use of web application attacks. then analysis is done an tests of the penetration tests are compiled.

Explanation:

6 0

3 years ago

What volume (mL) of concentrated solution of magnesium chloride (9.00 M) must be diluted to 350. mL to make a 2.75 M solution of

zalisa [80]

$❤Answer$

Volume of 106.9 mL from the concentrated solution should be taken and diluted to 350 mL.

⠀

Main I'd On Indian Brainly Is - HeartCrush

$⚡ Explantion$

We can use the formula. 

c1v1 =c2v2

Where c1 is the concentration and v1 is volume of the concentrated solution. 

c2 is the concentration

and v2 is the volume of the diluted solution to be prepared

9.00 M x V1 = 2.75 M x 350 mL

V1 = 106.9 mL

Volume of 106.9 mL from the concentrated solution should be taken and diluted to 350 mL.

3 0

3 years ago

An element has two isotopes, A and B, with mass numbers of 32.0 and 33.0 respectively. The relative atomic mass is 32.3. The per

vlada-n [284]

Answer:

d) A - 70% B - 30%

Explanation:

If x is the abundance of A, and 1−x is the abundance of B, then:

x (32.0) + (1−x) (33.0) = 32.3

32x + 33 − 33x = 32.3

33 − x = 32.3

x = 0.7

The abundance of A is 70%, and the abundance of B is 30%.

7 0

3 years ago

Read 2 more answers