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3 years ago

Is there more than one million,less the one million or more than one million milligrams in one kilogram

Mathematics

1 answer:

mamaluj [8]3 years ago

8 0

1 kilo gram is 1000 grams. 1 gram is 1000 milligrams. Think you can solve the rest? :)

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PLS HELP ME WITH GEOMETRY PLSAND THANK YOU

Alecsey [184]

Answer:

Yes

Step-by-step explanation:

They are equal acute triangles, are congurent. Your welcom

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2 years ago

1/3(12-6x)=4-2x I need help pls

Oksi-84 [34.3K]

Answer:

no solution

Step-by-step explanation:

1/3(12-6x)=4-2x

4-1.3x=4-2x

4=4-0.7x

0=0.7x

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3 years ago

Given a set of data with the Regression Line: y = 3.5x + 18.5

Tomtit [17]

Answer:

1.5

Step-by-step explanation:

$y=3.5*100+18.5=368.5\\rv=370-368.5=1.5$

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3 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

$F = \dfrac{9}{6^x}$

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

$W = \int\limits^{x_2}_{x_1} {F(x)} \, dx$

with $x_1$ and $x_2$ the initial and final displacements respectively.

From the question, $x_1 =0$ and $x_2 = 12$ .

Then

$W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx$

Evaluating the indefinite integral,

$\int\limits \dfrac{9}{6^x} \, dx =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx$

From the rules of integration,

$\int\limits a^x\, dx = \dfrac{a^x}{\ln a}$

$9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x$

Returning the limits,

$\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}$

4 0

3 years ago

Find the sum and express it in simplest form (6u-7c-6)+(-2u+4c)

Daniel [21]

4u+3c-6 is thats what its asking for? just puting the same variables together

4 0

2 years ago

Read 2 more answers