Answer:
Option 3 - Grignard reagents are strong bases and option 4 - Grignard reagents are strong nucleophiles
Explanation:
The carbon in grignard reagent has a very strong carbanionic character which gives grignard reaction it's unique characteristic of a strong base and strong nucleophile.
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The given question is incomplete. the complete question is:
Calculate the volume in liters of a 0.91 M magnesium fluoride solution that contains 249.2 g of magnesium fluoride . Round your answer to 2 significant digits.
Answer: 4.4 Liters
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
To calculate the moles, we use the equation:
=volume of solution in L
Thus the volume in liters is 4.4 L
The sample P2O3 ia made P, phosphorus and oxygen elements.
One mole of P2O3 has 2 mole P and 3 mole O
Thus the molar ratio is 2:3
The number of moles of silver oxide (I) needed to produce 4 moles of silver is 2 moles
<h3>Stoichiometry </h3>
From the question, we are to determine the number of moles of silver oxide (I) needed to produce 4 moles of silver
First, we will write the balaced chemical equation for the decomposition of silver oxide (I)
2Ag₂O(s) → 4Ag(s) + O₂(g)
This means, 2 moles of silver oxide (I) [Ag₂O] decomposes to give 4 moles of <u>silver </u>and 1 mole of oxygen gas.
From the <em>balanced chemical equation</em>, it is easy to deduce the number of moles of silver oxide (I) that would give 4 moles of silver.
Hence, the number of moles of silver oxide (I) needed to produce 4 moles of silver is 2 moles
Learn more on Stoichiometry here: brainly.com/question/18834543
Answer:
pH = 4.27. Porcentaje de disociación: 0.03%
Explanation:
El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
Donde la constante de equilibrio, Ka, es
Ka = 1.65x10⁻⁸ = [H⁺] [X⁻] / [HX]
Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:
[H⁺] = [X⁻]
[HX] es:
20g * (1mol/55g) = 0.3636moles / 2.100L = 0.1732M
Reemplazando es Ka:
1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]
2.858x10⁻⁹ = [H⁺]²
5.35x10⁻⁵M = [H⁺]
pH = -log[H⁺]
<h3>pH = 4.27</h3>
El porcentaje de disociacion es [X⁻] / [HX] inicial * 100
Reemplazando
5.35x10⁻⁵M / 0.1732M * 100
<h3>0.03%</h3>
