Question

What volume of 1.25 M sodium hydroxide (NaOH) solution can be prepared using 60.0 g of sodium hydroxide? (The mass of one mole of NaOH is 40.0 g.)
0.667 L
0.833 L
1.20 L
1.88L

Answer 1

Answer:

The answer is

1.20 L

Explanation:

Since the concentration , mass and molar mass of NaOH has been given we use the formula

$C = \frac{m}{M \times v}$

To find the volume

where

C is the concentration

m is the mass

M is the molar mass

v is the volume

Making volume the subject we have

$v = \frac{m}{C \times M}$

From the question

C = 1.25 M

m = 60 g

M = 40.0 g/mol

Substitute the values into the above formula and solve for the volume

We have

$v = \frac{60}{1.25 \times 40} \\ v = \frac{60}{50} \\ v = \frac{6}{5}$

We have the final answer as

Volume = 1.20 L

Hope this helps you