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Naya [18.7K]
3 years ago
15

What's the answer for B and C

Mathematics
1 answer:
Sophie [7]3 years ago
6 0

9514 1404 393

Answer:

  b = -5

  c = -2

Step-by-step explanation:

The explicit form of a sequence with common ratio r and first term a1 is ...

  an = a1(r^(n-1))

Matching the forms, we see that ...

  b is the first term of the sequence: -5.

  c is the common ratio: 10/-5 = -2.

In summary, ...

  b = -5, c = -2

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Point T is on line segment \overline{SU} SU . Given ST=12ST=12 and TU=3,TU=3, determine the length \overline{SU}. SU
vova2212 [387]

Answer:

SU = 15

Step-by-step explanation:

Given that,

Point T is on line segment SU. So,

SU = ST + TU

Putting all the values, we get :

SU = 12 + 3

SU = 15

Hence, the length of SU is 15 units.

3 0
3 years ago
Look at the picture please and solve, if its wrong ill report you for just picking a random answer
Sveta_85 [38]

Answer: - (27/40)

Step-by-step explanation:

-(3/8) / (5/9) is the same as -(3/8) × (9/5)

-((3×9) / (8×5))

-(27/40)

7 0
4 years ago
Does this equation have exactly one solution ​
Alex73 [517]

Answer:

13x + 7 = 9x - 33 + 4x \\ 7 + 33 = 13x - 13x \\  \\ 40 = 0 \\  \\ no

6 0
3 years ago
3 times a number is 42 what is the number?
oksano4ka [1.4K]


the number would be 14.

in order for you to figure this out you divide.

42/3=14  and

14 * 3 = 42

hope this helps.

4 0
3 years ago
Read 2 more answers
The table below shows the scores of a group of students on a 10-point quiz.Test ScoreFrequency3 54 15 16 27 28 49 310 1The mean
Katarina [22]

Explanation

Part A

We can use the formula below to find the mean.

\text{Mean}=\sum ^{}_{}(\frac{fx}{f})

We will then have;

\begin{gathered} \text{Mean = }\frac{5\times3+4\times1+5\times1+6\times2+7\times2+8\times4+9\times3+10\times1}{19}=\frac{15+4+5+12+14+32+27+10}{19} \\ =\frac{119}{19}=6.2632 \end{gathered}

Mean = 6.2632

Part B

Since the data set is odd.

\begin{gathered} \text{Median}=\frac{(n+1)}{2}^{th}\text{observation} \\ =\text{Value of }\frac{\text{(19+1)}}{2}^{th}\text{observation} \\ =\text{value of 10th observation} \end{gathered}

Answer: From the column of cumulative frequency cf, the median is 7

5 0
1 year ago
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