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zvonat [6]
3 years ago
13

If it takes 15 minutes to dry your hair with a 1.200 kW hair drier, how much energy is used in drying your hair?

Physics
2 answers:
Elodia [21]3 years ago
6 0
1.2 kW * 0.25 h = 0.300 kWh
Katen [24]3 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

The given data is as follows.

     Power = 1.200 kW,         Time = 15 minutes = \frac{15min}{60 min/hr} = 0.25 hour

     Energy = ?

Thus, calculate the energy by using the formula as follows.

               Power = \frac{Energy}{Time}

               Energy = Power × Time

                            = 1.200 kW × 0.25 hr

                            = 0.300 kWh

Thus, we can conclude that 0.300 kWh energy is used in drying your hair.

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A crate is pushed up each of the two ramps shown in the diagram below. Based on the concept that simple machines make work easie
Naddik [55]

Answer:

ramp b requires less force than ramp a

Explanation:

7 0
3 years ago
Object C has a mass of 3,600 kilograms. Object D has a mass of 900 kilograms. Both objects were placed on different planets so t
FinnZ [79.3K]
The correct answer would be 4
7 0
3 years ago
A 3.8 kg object is lifted 12 meters. approximately how much work is performed during the lifting.
Dmitry [639]

work done=446.9 J . so option (c) is correct.

Explanation:

the formula for work done is given by

W= F d

F= force= mg where m= mass and g= acceleration due to gravity

F= 3.8 (9.8)=37.24 J

so W=37.24 (12)

W=446.9 J

7 0
3 years ago
Read 2 more answers
Estimate the electric field at a point 2.40 cm perpendicular to the midpoint of a uniformly charged 2.00-m-long thin wire carryi
nadya68 [22]

Answer:

E = 1.85*10^{12}\frac{N}{C}

Explanation:

Hi!

The perpendicular distance 2.4cm, is much less than the distance to both endpoints of the wire, which is aprox 1m. Then the edge effect is negligible at this field point, and we can aproximate the wire as infinitely long.

The electric filed of an infinitely long wire is easy to calculate. Let's call z the axis along the wire. Because of its simmetry (translational and rotational), the electric field E must point in the radial direction,  and it cannot depende on coordinate z. To calculate the field Gauss law is used, as seen in the image, with a cylindrical gaussian surface. The result is:

E = \frac{\lambda}{2\pi \epsilon_0 r}\\\lambda=\text{charge per unit length}=\frac{4.95 \mu C}{2 m} = 2.475 \frac{C}{m}\\r=\text{perpendicular distance to wire}\\\epsilon_0=8.85*10^{-12}\frac{C^2}{Nm^2}

Then the electric field at the point of interest is estimated as:

E = \frac{\22.475}{2\pi*( 8.85*10^{-12})*(2.4*10^{-2})}\frac{N}{C}=1.85*10^{12}\frac{N}{C}

6 0
3 years ago
If each washer has a mass of 4.9 g, then the mass of two washers in kilograms would be Given that F = ma, and if 4 washers are a
zysi [14]

Given that,

Mass of each washer  = 4.9 g

We need to calculate the mass of two washers in kg

Using conversion of unit

Mass of each washer m= 4.9\times10^{-3}\ Kg

So, Mass of two washers is

M=2\times m

Put the value of m

M=2\times4.9\times10^{-3}\ k

M=0.0098\ Kg

If 4 washer are attached to the spring

We need to calculate the applied force on the car

Using formula of force

F=mg

Put the value into the formula

F=4\times4.9\times10^{-3}\times9.8

F=0.192\ N

Hence, (i), The mass of two washers is 0.0098 kg.

(ii). The applied force on the car is 0.192 N.

6 0
3 years ago
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