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3 years ago

Explain whether P waves or S waves are infra sound

1 answer:

8 0

Answer: S-waves only travel through solids, and P-waves can travel through solids and liquids. So S-waves because they can also be classified as infrasound waves.

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Explanation:

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A planet exerts a gravitational force of magnitude 4e22 N on a star. If the planet were 3 times closer to the star (that is, if

Alex_Xolod [135]

Answer:

$3.6\times10^{23} N$

Explanation:

$F=\frac{GmM}{r^2}=4\times10^{22} N$

$F'=\frac{GmM}{(r/3)^2}=9\frac{GmM}{r^2}=9\times4\times10^{22}=3.6\times10^{23} N$

7 0

2 years ago

How long does it take for an airplane to change its velocity from 140 m/s to 180 m/s if its

kobusy [5.1K]

Answer:

Explanation:

a = 4ms⁻², Vf = 180 m/s & Vi = 140m/s

a = $\frac{Vf-Vi}{t}$

4 = $\frac{180-140}{t}$

t = 40/4

t = 10sec

To Measure Distance Use third Equation of Motion:

2aS = Vf²-Vi²

S = $\frac{180*180 - 140*140}{2(4)}$

S = 12800/8 = 1600m

4 0

3 years ago

How do you calculate the mass of an object accelerating at22.35m/s2 with a force of 120N

Arte-miy333 [17]

Answer:

The mass of object is calculated as 5.36 kg

Explanation:

The known terms to find the mass are:

acceleration of object (a) = 22.35 $m/s^{2}$

Force exerted (F) = 120N

mass of an object (m) = ?

From Newton's second law of motion;

F = ma

or, 120 = m × 22.35

or, m= $\frac{120}{22.35}$ kg

∴ m = 5.36 kg

3 0

2 years ago

Air flows through an adiabatic turbine that is in steady operation. The air enters at 150 psia, 900oF, and 350 ft/s and leaves a

Nonamiya [84]

Answer:

$1486.5\frac{Btu}{s}$

Explanation:

The inlet specific volume of air is given by:

$v_1=\frac{RT_1}{P_1}\\\\v_1=\frac{(0.3704\frac{psia.ft^3}{lbm.R})(1360R)}{150psia}\\\\v_1=3.358\frac{ft^3}{lbm} \ \ \ \ \ \ \ \ \...i$

The mass flow rates is expressed as:

$\dot m=\frac{1}{v_1}A_1V_1\\\\\dot m=\frac{1}{3.358ft^3/psia}(0.1ft^2)(350ft/s)\\\\\dot m=10.42\frac{lbm}{s}$

The energy balance for the system can the be expresses in the rate form as:

$E_{in}-E_{out}=\bigtriangleup \dot E=0\\\\E_{in}=E_{out}\\\\\dot m(h_1+0.5V_1^2)=\dot W_{out}+\dot m(h_2+0.5V_2^2)+Q_{out}\\\\\dot W_{out}=\dot m(h_2-h_1+0.5(V_2^2-V_1^2))=-m({cp(T_2-t_1)+0.5(V_2^2-V_1^2)})\\\\\\\dot W_{out}=-(10.42lbm/s)[(0.25\frac{Btu}{lbm.\textdegree F})(300-900)\textdegree F+0.5((700ft/s)^2-(350ft/s)^2)(\frac{1\frac{Btu}{lbm}}{25037ft^2/s^2})]\\\\\\\\=1486.5\frac{Btu}{s}$

Hence, the mass flow rate of the air is 1486.5Btu/s

5 0

3 years ago

Directions: Using the T-chart below, compare balanced forces and unbalanced forces.

Salsk061 [2.6K]

Explanation:

unbalanced: a turning vehicle, apple falling on the ground, kicking a ball

balanced: floating on water, fruit hanging from tree, tug of war equally balanced teams

8 0

2 years ago