Suppose earth is a soid sphere which will attract the body towards its centre.So, acc. to law of gravitation force on the body will be,
F=G*m1m2/R^2
but we now that F=ma
and here accleration(a)=accleration due to gravity(g),so
force applied by earth on will also be mg
replace above F in formula by mg and solve,
F=G*mE*m/R^2 ( here mE is mass of earth and m is mass of body)
mg=G*mEm/R^2
so,
g =G*mE/R^2
Answer:
60kgm/s
Explanation:
Given parameters:
Mass of frisbee = 5kg
Final speed = 12m/s
Unknown:
Impulse of the frisbee = ?
Solution:
The impulse of the frisbee is the same as the change in momentum.
It is given as:
Impulse = mass (Final velocity - Initial velocity)
Impulse = 5(12 - 0) = 60kgm/s
I would say that I and IV because summer is I and fall is IV
The total momentum should come out to be <span>2.0 x 10^4 kilogram meters/second </span>
Answer:
the volume of liquid decreased due to evaporation from the exposed free surface of water so molecules got evaporated .
evaporation occurs at room temperature.