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Andrei [34K]
3 years ago
10

A. x € R B. x > 0 C. y > 0 D. y € R I need the answers right away!!

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0
Domain is x values and for this graph it’s all real numbers, so x is R
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Ethan is saving money in his piggy bank for his upcoming trip to Disney World. On the first day, he put in $12 and plans to add
PSYCHO15rus [73]

Answer:

A

12+7x=a

x=days

a=amount of money

B 12+7x=a

Step-by-step explanation:

7(18)=126

12+126=a

138=a

7 0
3 years ago
Read 2 more answers
Use the quadratic formula to solve the equation. -2x^2-x+7=0.
Furkat [3]
<span>-2x^2-x+7=0  
Variable with the highest degree's (exponent) constant, -2 is a, next variable's constant, -1 is b, the constant or number without a variable, 7 is c

using substitution put the numbers into the formula
</span>(-b±√(b^(2)-4ac))/(a^(2))

(-(-1)±√((-1)^(2)-4(-2)(7))/((-2)^(2)) simplify 

(1±√(1+56))/4

1±√(57)/4 is your answer
8 0
3 years ago
If 6x+4y=2 and 2x-7y=20 what is 8x-3y<br> ????<br> ???
Marizza181 [45]
Just add the two equations.

8x-3y=22

I hope this helps :)
4 0
3 years ago
E-1, e-2 and e-3 are three engineering students writing their assignments at night. Each of them starts at a different time and
Bas_tet [7]

E-3 will be the first student to start writing the assignment.

It is clearly stated in the statement that the order of starting the assignment and the order of the completion of the assignment is not the same, the digit in the name of the executive is also not same. This information puts some restrictions.

E-1 can neither be the first one to start nor the first one to complete. Similarly, E-2 cannot be the second one and E-3 cannot be the third one.

It is given that the last student (the third one) to start is the first student (the first one) to complete. This can neither be E-3 nor E-1. It is E-2

The final arrangement is as follows.

                                 Start           Complete

First                           E-3              E-2

Second                      E-1               E-3

Third                          E-2              E-1

E-3 is the first one to start writing the assignment.

More similar problems are solved in the link.

brainly.com/question/28391619?referrer=searchResults

#SPJ4

8 0
1 year ago
If x&gt;2, then x^2-a-6 / x^2-4=
nadezda [96]
We know that x > 2 ( or : x ≠ +/- 2 )
We have to factorize the numerator and the denominator:
x² - x - 6 = x² - 3 x + 2 x - 6 = x ( x - 3 ) + 2 ( x - 3 ) = ( x - 3 ) ( x + 2 )
x ² - 4 = ( x - 2 ) ( x + 2 )
\frac{(x-3)(x+2)}{(x-2)(x+2)}= \frac{x-3}{x-2}


7 0
3 years ago
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