To develop the problem, we require the values concerning the conservation of momentum, specifically as given for collisions.
By definition the conservation of momentum tells us that,
To find the speed at which the arrow impacts the apple we turn to the equation of time, in which,
The linear velocity of an object is given by
Replacing the equation of time we have to,
Velocity two is neglected since there is no velocity of said target before the collision, thus,
Clearing for m_2
Answer:
The two forces are;
1) Force 1 with magnitude of approximately 183.013 N, acting 30° to the left of the resultant force
2) Force 2 with magnitude of approximately 129.41 N acting at an inclination of 45° to the right of the resultant force
Explanation:
The given parameters are;
The (magnitude) of the resultant of two forces = 250 N
The angle of inclination of the two forces to the resultant = 30° and 45°
Let, F₁ and F₂ represent the two forces, we have;
F₁ is inclined 30° to the left of the resultant force and F₂ is inclined 45° to the right of the resultant force
The components of F₁ are = -F₁ × sin(30°)·i + F₁ × cos(30°)·j
The components of F₂ are = F₂ × sin(45°)·i + F₂ × cos(45°)·j
The sum of the forces = F₂ × sin(45°)·i + F₂ × cos(45°)·j + (-F₁ × sin(30°)·i + F₁ × cos(30°)·j) = 250·j
The resultant force, R = 250·j, which is in the y-direction, therefore, the component of the two forces in the x-direction cancel out
We have;
F₂ × sin(45°)·i = F₁ × sin(30°)·i
F₂ ·√2/2 = F₁/2
∴ F₁ = F₂ ·√2
∴ F₂ × cos(45°)·j + F₁ × cos(30°)·j = 250·j
Which gives;
F₂ × cos(45°)·j + F₂ ·√2 × cos(30°)·j = 250·j
F₂ × ((cos(45°) + √2 × cos(30°))·j = 250·j
F₂ × ((√2)/2 × (1 + √3))·j = 250·j
F₂ × ((√2)/2 × (1 + √3))·j = 250·j
F₂ = 250·j/(((√2)/2 × (1 + √3))·j) ≈ 129.41 N
F₂ ≈ 129.41 N
F₁ = √2 × F₂ = √2 × 129.41 N ≈ 183.013 N
F₁ ≈ 183.013 N
The two forces are;
A force with magnitude of approximately 183.013 N is inclined 30° to the left of the resultant force and a force with magnitude of approximately 129.41 N is inclined 45° to the right of the resultant force.
